How to convert interface{} to []int?

I am programming in Go programming language.

Say there's a variable of type interface{} that contains an array of integers. How do I convert interface{} back to []int?

I have tried

interface_variable.([]int)

The error I got is:

panic: interface conversion: interface is []interface {}, not []int

It's a []interface{} not just one interface{}, you have to loop through it and convert it:

the 2022 answer

https://go.dev/play/p/yeihkfIZ90U

func ConvertSlice[E any](in []any) (out []E) {
	out = make([]E, 0, len(in))
	for _, v := range in {
		out = append(out, v.(E))
	}
	return
}

the pre-go1.18 answer

http://play.golang.org/p/R441h4fVMw

func main() {
	a := []interface{}{1, 2, 3, 4, 5}
	b := make([]int, len(a))
	for i := range a {
		b[i] = a[i].(int)
	}
	fmt.Println(a, b)
}

As others have said, you should iterate the slice and convert the objects one by one.
Is better to use a type switch inside the range in order to avoid panics:

a := []interface{}{1, 2, 3, 4, 5}
b := make([]int, len(a))
for i, value := range a {
	switch typedValue := value.(type) {
	case int:
		b[i] = typedValue
		break
	default:
		fmt.Println("Not an int: ", value)
	}
}
fmt.Println(a, b)

http://play.golang.org/p/Kbs3rbu2Rw

Func return value is interface{} but real return value is []interface{}, so try this instead:

func main() {
    values := returnValue.([]interface{})
    for i := range values {
	    fmt.Println(values[i])
    }
}