英文:
Why wont these chars show when reversing string?
问题
我只会翻译文本内容，不会执行代码。以下是您提供的代码的翻译：
我只是想知道为什么当我反转并打印字符串中的每个字符时，这些亚洲字符不会显示出来。
package main
import "fmt"
func main() {
a := "The quick brown 狐 jumped over the lazy 犬"
var length int = len(a) - 1
for ; length > -1; length-- {
fmt.Printf("%c", a[length])
}
fmt.Println()
}
英文:
I'm just wondering why these asian characters in this string wont show up when I reverse and print the individual characters in the string.
package main
import "fmt"
func main() {
a := "The quick brown 狐 jumped over the lazy 犬"
var lenght int = len(a) - 1
for ; lenght > -1; lenght-- {
fmt.Printf("%c", a[lenght])
}
fmt.Println()
}
答案1
得分: 5
你正在通过字节而不是“逻辑字符”访问字符串数组。
为了更好地理解这个例子，首先将字符串作为一个符文数组分割，然后倒序打印符文。
package main
import "fmt"
func main() {
msg := "The quick brown 狐 jumped over the lazy 犬"
elements := make([]rune, 0)
for _, rune := range msg {
elements = append(elements, rune)
}
for i := len(elements) - 1; i >= 0; i-- {
fmt.Println(string(elements[i]))
}
}
更简洁的版本：http://play.golang.org/p/PYsduB4Rgq
package main
import "fmt"
func main() {
msg := "The quick brown 狐 jumped over the lazy 犬"
elements := []rune(msg)
for i := len(elements) - 1; i >= 0; i-- {
fmt.Println(string(elements[i]))
}
}
英文:
You are accessing the string array by byte not by 'logical character'
To better understand this example breaks the string first as an array of runes and then prints the rune backwards.
http://play.golang.org/p/bzbo7k6WZT
package main
import "fmt"
func main() {
msg := "The quick brown 狐 jumped over the lazy 犬"
elements := make([]rune, 0)
for _, rune := range msg {
elements = append(elements, rune)
}
for i := len(elements) - 1; i >= 0; i-- {
fmt.Println(string(elements[i]))
}
}
Shorter Version: http://play.golang.org/p/PYsduB4Rgq
package main
import "fmt"
func main() {
msg := "The quick brown 狐 jumped over the lazy 犬"
elements := []rune(msg)
for i := len(elements) - 1; i >= 0; i-- {
fmt.Println(string(elements[i]))
}
}
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