How to create JSON for Go struct

huangapple go评论90阅读模式
英文:

How to create JSON for Go struct

问题

我正在尝试使用Marshal函数从Go结构体创建JSON。创建的JSON不包含Person结构体。我错过了什么?

type Person struct {
    fn string
    ln string
}
type ColorGroup struct {
    ID     int
    Name   string
    Colors []string
    P      Person
}

per := Person{
    fn: "John",
    ln: "Doe",
}

group := ColorGroup{
    ID:     1,
    Name:   "Reds",
    Colors: []string{"Crimson", "Red", "Ruby", "Maroon"},
    P:      per,
}
b, err := json.Marshal(group)
if err != nil {
    fmt.Println("error:", err)
}
os.Stdout.Write(b)

生成的输出如下:

{"ID":1,"Name":"Reds","Colors":["Crimson","Red","Ruby","Maroon"],"P":{}}

我在输出中没有看到Person。

英文:

I am trying to use the Marshal function to create JSON from a Go struct. The JSON created does not contain the Person struct.
What am I missing?

http://play.golang.org/p/ASVYwDM7Fz

type Person struct {
	fn string
	ln string
}
type ColorGroup struct {
	ID     int
	Name   string
	Colors []string
	P      Person
}

per := Person{
	fn: "John",
	ln: "Doe",
}

group := ColorGroup{
	ID:     1,
	Name:   "Reds",
	Colors: []string{"Crimson", "Red", "Ruby", "Maroon"},
	P:      per,
}
b, err := json.Marshal(group)
if err != nil {
	fmt.Println("error:", err)
}
os.Stdout.Write(b)

The output generated is as follows:

{"ID":1,"Name":"Reds","Colors":["Crimson","Red","Ruby","Maroon"],"P":{}}

I don't see Person in the output.
http://golang.org/pkg/encoding/json/#Marshal

答案1

得分: 16

你缺少两个要点。

  1. 只有公共字段可以被转换为 JSON。
  2. 写入 JSON 的名称是字段的名称。在这种情况下,字段 Person 的名称是 P

请注意,我将 Person 结构体的字段名称更改为大写,并在 ColorGroup 结构体上添加了一个 json 标签,以指示我希望该字段以另一个名称进行序列化。通常会对大多数字段进行标记,并将名称更改为小写以与 JavaScript 的风格保持一致。

以下是翻译好的代码:

package main

import (
	"encoding/json"
	"fmt"
	"os"
)

func main() {
	type Person struct {
		Fn string
		Ln string
	}
	type ColorGroup struct {
		ID     int
		Name   string
		Colors []string
		P      Person `json:"Person"`
	}

	per := Person{
		Fn: "John",
		Ln: "Doe",
	}

	group := ColorGroup{
		ID:     1,
		Name:   "Reds",
		Colors: []string{"Crimson", "Red", "Ruby", "Maroon"},
		P:      per,
	}
	b, err := json.Marshal(group)
	if err != nil {
		fmt.Println("error:", err)
	}
	os.Stdout.Write(b)
}

输出结果为:

{"ID":1,"Name":"Reds","Colors":["Crimson","Red","Ruby","Maroon"],"Person":{"Fn":"John","Ln":"Doe"}}
英文:

You are missing two things.

  1. Only Public fields can be Marshaled to json.
  2. The name written to json is the name of the fieldd. In this case P for the field Person.

Notice that I changed the Fields name to be capital for the Person struct and that I added
a tag json on the ColorGroup Struct to indicate that I want that field to be serialized with another name. Is common to tag most of the fields and change the name to lowercase to be in sync with javascript's style.

http://play.golang.org/p/HQQ8r8iV7l

package main

import (
"encoding/json"
"fmt"
"os"
)

func main() {
type Person struct {
    Fn string
    Ln string
}
type ColorGroup struct {
    ID     int
    Name   string
    Colors []string
    P Person `json:"Person"`
}

per := Person{Fn: "John",
            Ln: "Doe",
    }

group := ColorGroup{
    ID:     1,
    Name:   "Reds",
    Colors: []string{"Crimson", "Red", "Ruby", "Maroon"},
    P: per,
}
b, err := json.Marshal(group)
if err != nil {
    fmt.Println("error:", err)
}
os.Stdout.Write(b)
}

Will output

{"ID":1,"Name":"Reds","Colors":["Crimson","Red","Ruby","Maroon"],"Person":{"Fn":"John","Ln":"Doe"}}

huangapple
  • 本文由 发表于 2014年6月12日 00:44:14
  • 转载请务必保留本文链接:https://go.coder-hub.com/24168259.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定