英文:
Golang: Testing several times using gobench
问题
我正在使用gobench进行工作，它可以帮助我们测试请求并获得有关性能的多个指标。
我对发送需要测试的URL的函数进行了修改。但是我发现无法多次调用该函数。
func GobenchMain(currectRoute *string) {
startTime := time.Now()
var done sync.WaitGroup
results := make(map[int]*Result)
...
}
之后我意识到gobench文件中的问题出现在以下部分：
signalChannel := make(chan os.Signal, 2)
signal.Notify(signalChannel, os.Interrupt, syscall.SIGTERM)
go func() {
_ = <-signalChannel
printResults(results, startTime)
os.Exit(0)
}()
最后，这是我期望进行调用的方式，并且可以进行多次请求。
package main
import (
"fmt"
"gobench"
)
var searchRoutes = []string{
"http:www.myurl.com/request1",
"http:www.myurl.com/request2",
"http:www.myurl.com/request3",
"http:www.myurl.com/request4",
}
func main() {
for i := 0; i < len(searchRoutes); i++ {
gobench.GobenchMain(&searchRoutes[i])
}
...
}
如何多次调用我的GobenchMain函数呢？
目前，由于代码中的os.Exit(0)，只能调用一次，如果我删除这行代码，程序将进入待机状态。
英文:
I'm working with gobench, wich help us to test a request and have several measures about the performance.
I did a modification for send the url that I need test in each call. But I found that it's not posible call the function twice or more times.
func GobenchMain(currectRoute *string) {
startTime := time.Now()
var done sync.WaitGroup
results := make(map[int]*Result)
...
}
After that I realize that the problem on gobench file is on this part:
signalChannel := make(chan os.Signal, 2)
signal.Notify(signalChannel, os.Interrupt, syscall.SIGTERM)
go func() {
_ = <-signalChannel
printResults(results, startTime)
os.Exit(0)
}()
Finally this is the way that I expect to do the call, and with this make more that one request.
package main
import (
"fmt"
"gobench"
)
var searchRoutes = []string{
"http:www.myurl.com/request1",
"http:www.myurl.com/request2",
"http:www.myurl.com/request3",
"http:www.myurl.com/request4",
}
func main() {
for i := 0; i < len(searchRoutes); i++ {
gobench.GobenchMain(&searchRoutes[i])
}
...
}
How can I call more that one time my GobeachMain?
;Currently with the code like that It's only possible call once, because after gobench get the result goes on os.exit(0), and if I remove this line, the program just goes to stand by
答案1
得分: 3
gobench从未设计成用作库。
只需像这样调用二进制文件
package main
import (
"log"
"os/exec"
)
func gobench(url string) {
cmd := exec.Command("gobench", url)
err := cmd.Run()
if err != nil {
log.Fatalf("Command finished with error: %v", err)
}
}
var searchRoutes = []string{
"http:www.myurl.com/request1",
"http:www.myurl.com/request2",
"http:www.myurl.com/request3",
"http:www.myurl.com/request4",
}
func main() {
for i := 0; i < len(searchRoutes); i++ {
gobench(searchRoutes[i])
}
}
英文:
gobench was never designed to be used as a library.
Just call the binary something like this
package main
import (
"log"
"os/exec"
)
func gobench(url string) {
cmd := exec.Command("gobench", url)
err := cmd.Run()
if err != nil {
log.Fatalf("Command finished with error: %v", err)
}
}
var searchRoutes = []string{
"http:www.myurl.com/request1",
"http:www.myurl.com/request2",
"http:www.myurl.com/request3",
"http:www.myurl.com/request4",
}
func main() {
for i := 0; i < len(searchRoutes); i++ {
gobench(searchRoutes[i])
}
}
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