英文:
Getting json dynamic key name as string?
问题
例如：
{"id":
{"12345678901234":
{"Account":"asdf",
"Password":"qwerty"
"LastSeen":"1397621470",
}
}
}
我一直在尝试编写一个程序，需要将id作为字符串获取，然后稍后使用它来检查LastSeen中的时间。我尝试使用simplejson和jsonq，但仍然无法弄清楚如何做到这一点。
英文:
For example:
{"id":
{"12345678901234":
{"Account":"asdf",
"Password":"qwerty"
"LastSeen":"1397621470",
}
}
}
A program I've been trying to make needs to get the id as a string and then later use it to check the time in LastSeen.
I've tried using simplejson and jsonq,but still cant figure out how to do that.
答案1
得分: 3
你可以使用RawMessage来简化代码（play with it) :
package main
import (
"encoding/json"
"fmt"
)
var data []byte = []byte(`{"id": {"12345678901234": {"Account":"asdf", "Password":"qwerty", "LastSeen":"1397621470"}}}`)
type Message struct {
Id string
Info struct {
Account string
Password string
LastSeen string
}
}
func main() {
var (
tmpmsg struct {
Data map[string]json.RawMessage `json:"id"`
}
msg Message
)
if err := json.Unmarshal(data, &tmpmsg); err != nil {
panic(err) //you probably wanna use or something instead
}
for id, raw := range tmpmsg.Data {
msg.Id = id
if err := json.Unmarshal(raw, &msg.Info); err != nil {
panic(err)
}
}
fmt.Printf("%+v\n", msg)
}
英文:
You can use RawMessage and make it much simpiler (play with it) :
package main
import (
"encoding/json"
"fmt"
)
var data []byte = []byte(`{"id": {"12345678901234": {"Account":"asdf", "Password":"qwerty", "LastSeen":"1397621470"}}}`)
type Message struct {
Id string
Info struct {
Account string
Password string
LastSeen string
}
}
func main() {
var (
tmpmsg struct {
Data map[string]json.RawMessage `json:"id"`
}
msg Message
)
if err := json.Unmarshal(data, &tmpmsg); err != nil {
panic(err) //you probably wanna use or something instead
}
for id, raw := range tmpmsg.Data {
msg.Id = id
if err := json.Unmarshal(raw, &msg.Info); err != nil {
panic(err)
}
}
fmt.Printf("%+v\n", msg)
}
答案2
得分: 1
在Golang博客上关于JSON的文章中，可以使用encoding/json包来实现。我创建了一个小程序来实现这个功能，代码如下：
package main
import (
"encoding/json"
"fmt"
)
var data []byte = []byte(`{"id": {"12345678901234": {"Account":"asdf", "Password":"qwerty", "LastSeen":"1397621470"}}}`)
type Message struct {
id string
LastSeen int64
}
var m Message
func main() {
var i interface {}
err := json.Unmarshal(data, &i)
if err != nil {
println("Error decoding data")
fmt.Printf("%s", err.Error())
return
}
m := i.(map[string]interface{})
for k, v := range m {
println(k)
im := v.(map[string]interface{})
for ik, iv := range im {
println("\t", ik)
jm := iv.(map[string]interface{})
for jk, jv := range jm {
println("\t\t", jk, ": ", jv.(string))
}
}
}
}
如果这段代码在Go的最佳实践方面存在问题，我向你道歉，因为我对这门语言还不熟悉。我知道其中有一些部分并不是完全必要的，比如Message类型的定义，但至少在你的数据上是可以工作的。
英文:
Looking at the Golang blog post on JSON <a href="http://blog.golang.org/json-and-go">here</a> it can be done using the encoding/json package. I created a small program to do this as follows:
package main
import (
"encoding/json"
"fmt"
)
var data []byte = []byte(`{"id": {"12345678901234": {"Account":"asdf", "Password":"qwerty", "LastSeen":"1397621470"}}}`)
type Message struct {
id string
LastSeen int64
}
var m Message
func main() {
var i interface {}
err := json.Unmarshal(data, &i)
if err != nil {
println("Error decoding data")
fmt.Printf("%s", err.Error())
return
}
m := i.(map[string]interface{})
for k, v := range m {
println(k)
im := v.(map[string]interface{})
for ik, iv := range im {
println("\t", ik)
jm := iv.(map[string]interface{})
for jk, jv := range jm {
println("\t\t", jk, ": ", jv.(string))
}
}
}
}
I apologise if this is poor in terms of Go best practices and such, I am new to the language. And I know that some elements of this aren't entirely necessary like the Message type definition but this works, at least on your data.
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