英文:
Assigning a type uintptr to uint64 in Golang
问题
我正在尝试将类型为 uintptr 的变量中的值赋给 Go 中的 uint64 变量。使用以下代码：
myVar = valFromSystem
会出现以下错误：
> 无法将类型为 uintptr 的 valFromSystem 分配给类型为 uint64 的 myVar
而尝试使用以下代码：
myVar = *valFromSystem
会出现以下错误：
> 无效的 valFromSystem 间接引用（类型为 uintptr）
有没有办法获取 valFromSystem 指向的值并赋给 myVar？
英文:
I'm trying to assign the value found in a variable of type uintptr to a uint64 variable in Go. Using
myVar = valFromSystem
gives me
> cannot use valFromSystem (type uintptr) as type uint64 in assignment
And trying
myVar = *valFromSystem
gives me
> invalid indirect of valFromSystem (type uintptr)
Is there a way to pull the value pointed to by valFromSystem to assign to myVar?
答案1
得分: 22
首先，将valFromSystem转换为unsafe.Pointer。unsafe.Pointer可以转换为任何指针类型。接下来，将unsafe.Pointer转换为指向valFromSystem指向的数据类型的指针，例如uint64。
ptrFromSystem = (*uint64)(unsafe.Pointer(valFromSystem))
如果你只想获取指针的值（而不是解引用它），你可以直接进行转换：
uint64FromSystem = uint64(valFromSystem)
不过请记住，在将指针用作整数时，应使用类型uintptr。
英文:
First, cast valFromSystem into an unsafe.Pointer. An unsafe.Pointer can be casted into any pointer type. Next, cast the unsafe.Pointer into a pointer to whatever type of data valFromSystem points to, e.g. an uint64.
ptrFromSystem = (*uint64)(unsafe.Pointer(valFromSystem))
If you just want to get the value of the pointer (without dereferencing it), you can use a direct cast:
uint64FromSystem = uint64(valFromSystem)
Though remember that you should use the type uintptr when using pointers as integers.
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