英文:
How to print the memory address of a slice in Golang?
问题
我在C语言方面有一些经验，对golang完全不熟悉。
func learnArraySlice() {
intarr := [5]int{12, 34, 55, 66, 43}
slice := intarr[:]
fmt.Printf("the len is %d and cap is %d \n", len(slice), cap(slice))
fmt.Printf("address of slice 0x%x add of Arr 0x%x \n", &slice, &intarr)
}
现在在golang中，切片是一个数组的引用，它包含指向数组的指针、切片的长度和切片的容量。但是这个切片也会在内存中分配空间，我想打印出那块内存的地址，但是无法做到。
英文:
I have some experience in C and I am totally new to golang.
func learnArraySlice() {
intarr := [5]int{12, 34, 55, 66, 43}
slice := intarr[:]
fmt.Printf("the len is %d and cap is %d \n", len(slice), cap(slice))
fmt.Printf("address of slice 0x%x add of Arr 0x%x \n", &slice, &intarr)
}
Now in golang slice is a reference of array which contains the pointer to an array len of slice and cap of slice but this slice will also be allocated in memory and i want to print the address of that memory. But unable to do that.
答案1
得分: 50
fmt.Printf("切片的地址 %p 数组的地址 %p \n", &slice, &intarr)
%p 会打印地址。
英文:
fmt.Printf("address of slice %p add of Arr %p \n", &slice, &intarr)
%p will print the address.
答案2
得分: 15
切片及其元素是可寻址的：
s := make([]int, 10)
fmt.Printf("第一个元素的地址：%p\n", &s[0])
fmt.Printf("切片本身的地址：%p\n", &s)
英文:
Slices and their elements are addressable:
s := make([]int, 10)
fmt.Printf("Addr of first element: %p\n", &s[0])
fmt.Printf("Addr of slice itself: %p\n", &s)
答案3
得分: 5
对于切片底层数组和数组的地址（在你的示例中它们是相同的），
package main
import "fmt"
func main() {
intarr := [5]int{12, 34, 55, 66, 43}
slice := intarr[:]
fmt.Printf("切片的长度为 %d，容量为 %d \n", len(slice), cap(slice))
fmt.Printf("切片的地址为 %p，数组的地址为 %p\n", &slice[0], &intarr)
}
输出结果：
切片的长度为 5，容量为 5
切片的地址为 0x1052f2c0，数组的地址为 0x1052f2c0
英文:
For the addresses of the slice underlying array and the array (they are the same in your example),
package main
import "fmt"
func main() {
intarr := [5]int{12, 34, 55, 66, 43}
slice := intarr[:]
fmt.Printf("the len is %d and cap is %d \n", len(slice), cap(slice))
fmt.Printf("address of slice %p add of Arr %p\n", &slice[0], &intarr)
}
Output:
the len is 5 and cap is 5
address of slice 0x1052f2c0 add of Arr 0x1052f2c0
答案4
得分: 1
package main
import (
"fmt"
"reflect"
"unsafe"
)
func main() {
intArr := [5]int{1, 2, 3, 4, 5}
intSlice := intArr[:]
fmt.Printf("切片地址= %p, 长度= %d, 容量= %d\n", &intSlice, len(intArr), cap(intArr))
fmt.Printf("数组地址= %p, 长度= %d, 容量= %d\n", &intArr, len(intArr), cap(intArr))
fmt.Printf("切片第一个元素地址=%p\n", &intSlice[0])
fmt.Printf("切片的底层数组地址=%p\n", intSlice)
fmt.Printf("切片的底层数组地址=%#v\n", *((*reflect.SliceHeader)(unsafe.Pointer(&intSlice))))
}
输出：
切片地址= 0xc0000a4018, 长度= 5, 容量= 5
数组地址= 0xc0000b6000, 长度= 5, 容量= 5
切片第一个元素地址=0xc0000b6000
切片的底层数组地址=0xc0000b6000
切片的底层数组地址=reflect.SliceHeader{Data:0xc0000b6000, Len:5, Cap:5}
英文:
package main
import (
"fmt"
"reflect"
"unsafe"
)
func main() {
intArr := [5]int{1, 2, 3, 4, 5}
intSlice := intArr[:]
fmt.Printf("slice addr= %p, len= %d, cap= %d\n", &intSlice, len(intArr), cap(intArr))
fmt.Printf("array addr= %p, len= %d, cap= %d\n", &intArr, len(intArr), cap(intArr))
fmt.Printf("slice first elem addr=%p\n", &intSlice[0])
fmt.Printf("backend array of slice addr=%p\n", intSlice)
fmt.Printf("backend array of slice addr=%#v\n", *((*reflect.SliceHeader)(unsafe.Pointer(&intSlice))))
}
output:
slice addr= 0xc0000a4018, len= 5, cap= 5
array addr= 0xc0000b6000, len= 5, cap= 5
slice first elem addr=0xc0000b6000
backend array of slice addr=0xc0000b6000
backend array of slice addr=reflect.SliceHeader{Data:0xc0000b6000, Len:5, Cap:5}
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