英文:
How could I convert an []interface{} into a []string in Go?
问题
我目前正在处理一段代码，其中涉及到一个类型为[]interface{}的变量。
它包含了一些值，我可以通过以下方式轻松访问：
// 假设args的类型为[]interface{}
name := args[0]
age := args[1] //等等...
这样做是可以的，但是我想要能够使用strings包中的Join函数，但通常会出错，因为它需要的是[]string类型而不是[]interface{}类型。
为了能够使用Join函数，最合适的解决方案是什么，我猜可能需要进行某种类型的转换？
英文:
I'm currently working with a bit of code at the moment, that involves a var with type []interface{}
It has values within it, that I could easily access like so:
//given that args is of type []interface{}
name := args[0]
age := args[1] //ect...
This is fine, but I'd like to be able to use the strings Join function, and it would typically error due to it requiring type []string and not type []interface{}.
What would be the most appropriate solution to be able to use the Join function, I'd guess maybe some sort on conversion?
答案1
得分: 4
你需要构建一个类型为[]string的新数组，以便使用strings.Join函数：
import "fmt"
import "strings"
func main() {
s1 := []interface{}{"a", "b", "c"}
s2 := make([]string, len(s1))
for i, s := range s1 {
s2[i] = s.(string)
}
fmt.Println(strings.Join(s2, ", "))
}
请参考相关的Golang FAQ条目：我可以将[]T转换为[]interface{}吗？
英文:
You need to construct a new array of type []string in order to use strings.Join:
import "fmt"
import "strings"
func main() {
s1 := []interface{}{"a", "b", "c"}
s2 := make([]string, len(s1))
for i, s := range s1 {
s2[i] = s.(string)
}
fmt.Println(strings.Join(s2, ", "))
}
See the related Golang FAQ entry: can I convert a []T to an []interface{}?
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