英文:
Go subprocess communication
问题
有一种方法可以与等待标准输入的子进程（shell脚本/Python脚本）进行通信。
例如，Python脚本（子进程）：
import sys
while True:
sys.stdout.write('%s\n' % eval(sys.stdin.readline()))
在Go程序中，我想创建这个Python脚本的子进程，并在需要时重复地向其标准输入提供输入，并获取其输出。可以通过向Go程序的标准输出写入或从文件中读取/写入来实现。
以下是我大致尝试的代码，但没有任何反应：
c := exec.Command("python", "-u add.py")
si, _ := c.StdinPipe()
so, _ := c.StdoutPipe()
c.Start()
si.Write([]byte("2+2\n"))
请注意，这只是一个示例，你需要根据你的实际需求进行适当的修改。
英文:
GO: Is there some way to communicate with a subprocess (shell script / python script), which is waiting for input on stdin?
e.g. python script (subprocess)
import sys
while True:
sys.stdout.write('%s\n'%eval(sys.stdin.readline()))
In the go program, I want to create a subprocess of this python script and provide it input on its stdin, whenever necessary and repeatedly, and take its output. Writing on stdout of Go program or reading/writing from a file will also do.
This is roughly what I am trying, but nothing happens -
c := exec.Command("python", "-u add.py")
si,_ := c.StdinPipe()
so,_ := c.StdoutPipe()
c.Start()
si.Write([]byte("2+2\n")
答案1
得分: 5
这是您的Go代码的工作版本（Python代码未更改）。
注意：检查所有错误，修复了-u标志，使用bufio读取一行，并使用Wait等待进程结束。
import (
"bufio"
"fmt"
"log"
"os/exec"
)
func main() {
c := exec.Command("python", "-u", "add.py")
si, err := c.StdinPipe()
if err != nil {
log.Fatal(err)
}
so, err := c.StdoutPipe()
if err != nil {
log.Fatal(err)
}
reader := bufio.NewReader(so)
err = c.Start()
if err != nil {
log.Fatal(err)
}
// 现在进行一些数学计算
for i := 0; i < 10; i++ {
sum := fmt.Sprintf("2+%d\n", i)
_, err = si.Write([]byte(sum))
if err != nil {
log.Fatal(err)
}
answer, err := reader.ReadString('\n')
if err != nil {
log.Fatal(err)
}
fmt.Printf("对于 %q 的答案是 %q\n", sum, answer)
}
// 关闭输入并等待退出
si.Close()
so.Close()
c.Wait()
}
运行结果为：
对于 "2+0\n" 的答案是 "2\n"
对于 "2+1\n" 的答案是 "3\n"
对于 "2+2\n" 的答案是 "4\n"
对于 "2+3\n" 的答案是 "5\n"
对于 "2+4\n" 的答案是 "6\n"
对于 "2+5\n" 的答案是 "7\n"
对于 "2+6\n" 的答案是 "8\n"
对于 "2+7\n" 的答案是 "9\n"
对于 "2+8\n" 的答案是 "10\n"
对于 "2+9\n" 的答案是 "11\n"
英文:
Here is a working version of your go code (python code is unchanged).
Note: checking of all errors, fixed -u flag, use of bufio to read a line, and Wait to wait for end of process.
import (
"bufio"
"fmt"
"log"
"os/exec"
)
func main() {
c := exec.Command("python", "-u", "add.py")
si, err := c.StdinPipe()
if err != nil {
log.Fatal(err)
}
so, err := c.StdoutPipe()
if err != nil {
log.Fatal(err)
}
reader := bufio.NewReader(so)
err = c.Start()
if err != nil {
log.Fatal(err)
}
// Now do some maths
for i := 0; i < 10; i++ {
sum := fmt.Sprintf("2+%d\n", i)
_, err = si.Write([]byte(sum))
if err != nil {
log.Fatal(err)
}
answer, err := reader.ReadString('\n')
if err != nil {
log.Fatal(err)
}
fmt.Printf("Answer to %q is %q\n", sum, answer)
}
// Close the input and wait for exit
si.Close()
so.Close()
c.Wait()
}
Which produces
Answer to "2+0\n" is "2\n"
Answer to "2+1\n" is "3\n"
Answer to "2+2\n" is "4\n"
Answer to "2+3\n" is "5\n"
Answer to "2+4\n" is "6\n"
Answer to "2+5\n" is "7\n"
Answer to "2+6\n" is "8\n"
Answer to "2+7\n" is "9\n"
Answer to "2+8\n" is "10\n"
Answer to "2+9\n" is "11\n"
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