定义一个在golang中返回可变大小切片的函数。

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英文:

Defining a function that returns a slice of variable size in golang

问题

我想要构建一个可以返回任意大小切片的函数。我知道可以这样做:

func BuildSlice() [100]int { return [100]int{} }

但是我希望能够从同一个函数返回不同大小的切片。类似这样:

func BuildSlice(size int) []int { return make([]int, size) }

我尝试了上述方法以及:

func BuildSlice(size int) []int { return [size]int{} }

请指点我正确的方向。

英文:

I would like to build a function that returns a slice of any size. I know I can do

func BuildSlice() [100]int { return [100]int{} }

but I would like to be able to return slices of different sizes from the same function. Something like:

func BuildSlice(int size) [...]int { return [size]int{} }

I've tried the above as well as

func BuildSlice(size int) []int { return [size]int{} }

Please point me in the right direction.

答案1

得分: 54

首先,切片已经是“可变大小”的:[100]int[...]int是数组类型的定义。

[]int是切片的正确语法,你可以这样实现该函数:

func BuildSlice(size int) []int {
    return make([]int, size)
}

这将返回一个具有所需大小的零值切片,类似于你的数组版本。

英文:

First of all, slices are already of "variable size": [100]int and [...]int are array type definitions.

[]int is the correct syntax for a slice, and you could implement the function as:

func BuildSlice(size int) []int {
    return make([]int, size)
}

This will return a slice of zero values with the desired size, similar to what your array version does.

答案2

得分: 5

《Go编程语言规范》

创建切片、映射和通道

内置函数make接受一个类型T作为参数,该类型必须是切片、映射或通道类型,可选地跟随一个特定类型的表达式列表。它返回一个类型为T的值(而不是*T)。内存的初始化方式如初始值节所述。

调用 类型T 结果

make(T, n) 切片 长度为n、容量为n的类型为T的切片
make(T, n, m) 切片 长度为n、容量为m的类型为T的切片

大小参数n和m必须是整数类型或无类型的。常量大小参数必须是非负的,并且可以由int类型的值表示。如果提供了n和m,并且它们都是常量,则n必须不大于m。如果n在运行时为负数或大于m,则会发生运行时恐慌。

例如:

s := make([]int, 10, 100)       // 切片的长度为10,容量为100
s := make([]int, 1e3)           // 切片的长度和容量都为1000
s := make([]int, 1<<63)         // 非法:切片的长度不能由int类型的值表示
s := make([]int, 10, 0)         // 非法:切片的长度大于容量

例如:

package main

import "fmt"

func main() {
    s := make([]int, 7, 42)
    fmt.Println(len(s), cap(s))
    t := make([]int, 100)
    fmt.Println(len(t), cap(t))
}

输出:

7 42
100 100
英文:

> The Go Programming Language Specification
>
> Making slices, maps and channels
>
> The built-in function make takes a type T, which must be a slice, map
> or channel type, optionally followed by a type-specific list of
> expressions. It returns a value of type T (not *T). The memory is
> initialized as described in the section on initial values.
>
> Call Type T Result
>
> make(T, n) slice slice of type T with length n and capacity n
> make(T, n, m) slice slice of type T with length n and capacity m
>
> The size arguments n and m must be of integer type or untyped. A
> constant size argument must be non-negative and representable by a
> value of type int. If both n and m are provided and are constant, then
> n must be no larger than m. If n is negative or larger than m at run
> time, a run-time panic occurs.
>
> s := make([]int, 10, 100) // slice with len(s) == 10, cap(s) == 100
> s := make([]int, 1e3) // slice with len(s) == cap(s) == 1000
> s := make([]int, 1<<63) // illegal: len(s) is not representable by a value of type int
> s := make([]int, 10, 0) // illegal: len(s) > cap(s)

For example,

package main

import &quot;fmt&quot;

func main() {
	s := make([]int, 7, 42)
	fmt.Println(len(s), cap(s))
	t := make([]int, 100)
	fmt.Println(len(t), cap(t))
}

Output:

7 42
100 100

huangapple
  • 本文由 发表于 2014年3月11日 13:42:02
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