英文:
How to declare interface array in Go
问题
我在创建一个接口数组的简单任务中遇到了困难。以下是我的代码：
var result float64for i := 0; i < len(diff); i++ {result += diff[i]}result = 1 / (1 + math.Sqrt(result))id1 := user1.UserIdid2 := user2.UserIduser1.Similar[id2] = [2]interface{id2, result}user2.Similar[id1] = [2]interface{id1, result}
其中result是一个float64类型，user*.UserId是一个int类型。
我的错误信息是：
语法错误：接口类型中不允许使用名称列表
英文:
I am having difficulty in what should be a trivial task of creating an interface array. Here is my code,
var result float64for i := 0; i < len(diff); i++ {result += diff[i]}result = 1 / (1 + math.Sqrt(result))id1 := user1.UserIdid2 := user2.UserIduser1.Similar[id2] = [2]interface{id2, result}user2.Similar[id1] = [2]interface{id1, result}
result is a float and user*.UserId is an int.
My error message is
syntax error: name list not allowed in interface type
答案1
得分: 7
例如，
package mainimport ("fmt")func main() {x, y := 1, "@"a := [2]interface{}{x, y}fmt.Println(a)b := [2]interface{}{0, "x"}fmt.Println(b)}
输出：
[1 @][0 x]
英文:
For example,
package mainimport ("fmt")func main() {x, y := 1, "@"a := [2]interface{}{x, y}fmt.Println(a)b := [2]interface{}{0, "x"}fmt.Println(b)}
Output:
[1 @][0 x]
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