英文:
Generating prime numbers in Go
问题
我希望我的if
语句只在满足以下两个条件时为真:
for i := 2; i <= 10; i++ {
if i%i == 0 && i%1 == 0 {
// 满足条件的情况
} else {
// 不满足条件的情况
}
}
在这种情况下,每个可能的数字都会通过这些条件,但我只想让只能被自身和1整除的数字通过,除了第一个数字'2'之外。我该如何做到这一点?
谢谢
英文:
EDIT: The question essentially asks to generate prime numbers up to a certain limit. The original question follows.
I want my if
statement to become true if only these two conditions are met:
for i := 2; i <= 10; i++ {
if i%i == 0 && i%1 == 0 {
} else {
}
}
In this case every possible number gets past these conditions, however I want only the numbers 2, 3, 5, 7, 11... basically numbers that are divisible only with themselves and by 1 to get past, with the exception being the very first '2'. How can I do this?
Thanks
答案1
得分: 14
似乎你正在寻找质数。然而,你描述的条件是不充分的。实际上,你需要使用一个算法来生成它们(最可能是在一定的限制范围内)。
这是一个实现 Atkin筛法 的代码,它是古老的埃拉托斯特尼筛法的优化变体。
演示:http://play.golang.org/p/XXiTIpRBAu
为了完整起见:
package main
import (
"fmt"
"math"
)
// 只会生成小于等于N的质数
const N = 100
func main() {
var x, y, n int
nsqrt := math.Sqrt(N)
is_prime := [N]bool{}
for x = 1; float64(x) <= nsqrt; x++ {
for y = 1; float64(y) <= nsqrt; y++ {
n = 4*(x*x) + y*y
if n <= N && (n%12 == 1 || n%12 == 5) {
is_prime[n] = !is_prime[n]
}
n = 3*(x*x) + y*y
if n <= N && n%12 == 7 {
is_prime[n] = !is_prime[n]
}
n = 3*(x*x) - y*y
if x > y && n <= N && n%12 == 11 {
is_prime[n] = !is_prime[n]
}
}
}
for n = 5; float64(n) <= nsqrt; n++ {
if is_prime[n] {
for y = n * n; y < N; y += n * n {
is_prime[y] = false
}
}
}
is_prime[2] = true
is_prime[3] = true
primes := make([]int, 0, 1270606)
for x = 0; x < len(is_prime)-1; x++ {
if is_prime[x] {
primes = append(primes, x)
}
}
// primes现在是一个包含所有小于等于N的质数的切片
// 让我们打印它们
for _, x := range primes {
fmt.Println(x)
}
}
英文:
It seems you are looking for prime numbers. However the conditions you described are not sufficient. In fact you have to use an algorithm to generate them (up to a certain limit most probably).
This is an implementation of the Sieve of Atkin which is an optimized variation of the ancient Sieve of Eratosthenes.
Demo: http://play.golang.org/p/XXiTIpRBAu
For the sake of completeness:
package main
import (
"fmt"
"math"
)
// Only primes less than or equal to N will be generated
const N = 100
func main() {
var x, y, n int
nsqrt := math.Sqrt(N)
is_prime := [N]bool{}
for x = 1; float64(x) <= nsqrt; x++ {
for y = 1; float64(y) <= nsqrt; y++ {
n = 4*(x*x) + y*y
if n <= N && (n%12 == 1 || n%12 == 5) {
is_prime[n] = !is_prime[n]
}
n = 3*(x*x) + y*y
if n <= N && n%12 == 7 {
is_prime[n] = !is_prime[n]
}
n = 3*(x*x) - y*y
if x > y && n <= N && n%12 == 11 {
is_prime[n] = !is_prime[n]
}
}
}
for n = 5; float64(n) <= nsqrt; n++ {
if is_prime[n] {
for y = n * n; y < N; y += n * n {
is_prime[y] = false
}
}
}
is_prime[2] = true
is_prime[3] = true
primes := make([]int, 0, 1270606)
for x = 0; x < len(is_prime)-1; x++ {
if is_prime[x] {
primes = append(primes, x)
}
}
// primes is now a slice that contains all primes numbers up to N
// so let's print them
for _, x := range primes {
fmt.Println(x)
}
}
答案2
得分: 8
这是一个使用Go语言实现的埃拉托斯特尼筛法:
package main
import "fmt"
// 返回小于N的质数列表
func sieveOfEratosthenes(N int) (primes []int) {
b := make([]bool, N)
for i := 2; i < N; i++ {
if b[i] == true { continue }
primes = append(primes, i)
for k := i * i; k < N; k += i {
b[k] = true
}
}
return
}
func main() {
primes := sieveOfEratosthenes(100)
for _, p := range primes {
fmt.Println(p)
}
}
这段代码实现了埃拉托斯特尼筛法,用于找出小于N的所有质数。在主函数中,我们调用sieveOfEratosthenes
函数并打印出返回的质数列表。
英文:
Here's a golang sieve of Eratosthenes
package main
import "fmt"
// return list of primes less than N
func sieveOfEratosthenes(N int) (primes []int) {
b := make([]bool, N)
for i := 2; i < N; i++ {
if b[i] == true { continue }
primes = append(primes, i)
for k := i * i; k < N; k += i {
b[k] = true
}
}
return
}
func main() {
primes := sieveOfEratosthenes(100)
for _, p := range primes {
fmt.Println(p)
}
}
答案3
得分: 5
获取“只能被自身和1整除”的数字,也被称为质数的最简单方法是:http://en.wikipedia.org/wiki/Sieve_of_Eratosthenes
这不是一个“简单的if语句”。
英文:
The simplest method to get "numbers that are divisible only with themselves and by 1", which are also known as prime numbers is: http://en.wikipedia.org/wiki/Sieve_of_Eratosthenes
It's not a "simple if statement".
答案4
得分: 1
如果你不介意它们可能不是质数的非常小的几率(在这种情况下为9.1e-13),你可以像这样使用math/big中的ProbablyPrime函数(play):
import (
"fmt"
"math/big"
)
func main() {
for i := 2; i < 1000; i++ {
if big.NewInt(int64(i)).ProbablyPrime(20) {
fmt.Printf("%d 可能是质数\n", i)
} else {
fmt.Printf("%d 绝对不是质数\n", i)
}
}
}
只需将常量20更改为你认为足够确定它们是质数的值。
英文:
If you don't mind a very small chance (9.1e-13 in this case) of them not being primes you can use ProbablyPrime from math/big like this (play)
import (
"fmt"
"math/big"
)
func main() {
for i := 2; i < 1000; i++ {
if big.NewInt(int64(i)).ProbablyPrime(20) {
fmt.Printf("%d is probably prime\n", i)
} else {
fmt.Printf("%d is definitely not prime\n", i)
}
}
}
Just change the constant 20 to be as sure as you like that they are primes.
答案5
得分: 1
简单的方式(修正):
package main
import "math"
const n = 100
func main() {
print(1, " ", 2)
L: for i := 3; i <= n; i += 2 {
m := int(math.Floor(math.Sqrt(float64(i))))
for j := 2; j <= m; j++ {
if i%j == 0 {
continue L
}
}
print(" ", i)
}
}
以上是给定的代码段,它使用简单的方式来打印出从1到100之间的所有素数。
英文:
Simple way(fixed):
package main
import "math"
const n = 100
func main() {
print(1, " ", 2)
L: for i := 3; i <= n; i += 2 {
m := int(math.Floor(math.Sqrt(float64(i))))
for j := 2; j <= m; j++ {
if i%j == 0 {
continue L
}
}
print(" ", i)
}
}
答案6
得分: 1
只需将外部循环中的100更改为您想要找到的质数的限制即可。干杯!
for i:=2; i<=100; i++{
isPrime:=true
for j:=2; j<i; j++{
if i % j == 0 {
isPrime = false
}
}
if isPrime == true {
fmt.Println(i)
}
}
}
英文:
just change the 100 in the outer for loop to the limit of the prime number you want to find. cheers!!
for i:=2; i<=100; i++{
isPrime:=true
for j:=2; j<i; j++{
if i % j == 0 {
isPrime = false
}
}
if isPrime == true {
fmt.Println(i)
}
}
}
答案7
得分: 0
请尝试这个代码,通过检查所有边界情况和优化的方式来找到数字,并在函数返回true时运行逻辑。
package main
import (
"math"
"time"
"fmt"
)
func prime(n int) bool {
if n < 1 {
return false
}
if n == 2 {
return true
}
if n % 2 == 0 && n > 2 {
return false
}
var maxDivisor = int(math.Floor(math.Sqrt(float64 (n))))
//d := 3
for d:=3 ;d <= 1 + maxDivisor; d += 2 {
if n%d == 0 {
return false
}
}
return true
}
//======Test Function=====
func main() {
// var t0 = time.Time{}
var t0= time.Second
for i := 1; i <= 1000; i++ {
fmt.Println(prime(i))
}
var t1= time.Second
println(t1 - t0)
}
这段代码是一个用于判断素数的函数。它通过检查给定的数字是否能被除了1和自身以外的其他数字整除来确定是否为素数。在main
函数中,它会打印从1到1000的所有数字是否为素数,并计算执行时间。
英文:
Here try this by checking all corner cases and optimised way to find you numbers and run the logic when the function returns true.
package main
import (
"math"
"time"
"fmt"
)
func prime(n int) bool {
if n < 1 {
return false
}
if n == 2 {
return true
}
if n % 2 == 0 && n > 2 {
return false
}
var maxDivisor = int(math.Floor(math.Sqrt(float64 (n))))
//d := 3
for d:=3 ;d <= 1 + maxDivisor; d += 2 {
if n%d == 0 {
return false
}
}
return true
}
//======Test Function=====
func main() {
// var t0 = time.Time{}
var t0= time.Second
for i := 1; i <= 1000; i++ {
fmt.Println(prime(i))
}
var t1= time.Second
println(t1 - t0)
}
答案8
得分: 0
package main
import (
"fmt"
)
func main() {
//runtime.GOMAXPROCS(4)
ch := make(chan int)
go generate(ch)
for {
prime := <-ch
fmt.Println(prime)
ch1 := make(chan int)
go filter(ch, ch1, prime)
ch = ch1
}
}
func generate(ch chan int) {
for i := 2; ; i++ {
ch <- i
}
}
func filter(in, out chan int, prime int) {
for {
i := <-in
if i%prime != 0 {
out <- i
}
}
}
这是一个使用Go语言编写的简单程序。它实现了一个无限生成素数的算法。程序通过使用goroutine和通道来实现并发计算。在主函数中,首先创建了一个整数类型的通道ch,并启动了一个goroutine来生成素数,并将素数发送到通道ch中。然后,通过一个无限循环,从通道ch中接收素数,并打印出来。接着,创建了一个新的通道ch1,并启动一个goroutine来过滤掉不是素数的数,并将结果发送到通道ch1中。最后,将通道ch1赋值给通道ch,继续下一轮循环。这样就实现了一个无限生成素数的算法。
英文:
package main
import (
"fmt"
)
func main() {
//runtime.GOMAXPROCS(4)
ch := make(chan int)
go generate(ch)
for {
prime := <-ch
fmt.Println(prime)
ch1 := make(chan int)
go filter(ch, ch1, prime)
ch = ch1
}
}
func generate(ch chan int) {
for i := 2; ; i++ {
ch <- i
}
}
func filter(in, out chan int, prime int) {
for {
i := <-in
if i%prime != 0 {
out <- i
}
}
}
答案9
得分: 0
一个类似C语言(老派)的逻辑,
package main
import "fmt"
func main() {
var num = 1000
for j := 2; j < num ; j++ {
var flag = 0
for i := 2; i <= j/2 ; i++ {
if j % i == 0 {
flag = 1
break
}
}
if flag == 0 {
fmt.Println(j)
}
}
}
英文:
A C
like logic (old school),
package main
import "fmt"
func main() {
var num = 1000
for j := 2; j < num ; j++ {
var flag = 0
for i := 2; i <= j/2 ; i++ {
if j % i == 0 {
flag = 1
break
}
}
if flag == 0 {
fmt.Println(j)
}
}
}
答案10
得分: 0
生成小于某个限制的素数的简单解决方案:
func findNthPrime(number int) int {
if number < 1{
fmt.Println("请提供正数")
return number
}
var primeCounter, nthPrimeNumber int
for i:=2; primeCounter < number; i++{
isPrime := true
for j:=2; j <= int(math.Sqrt(float64(i))) && i != 2 ; j++{
if i % j == 0{
isPrime = false
}
}
if isPrime{
primeCounter++
nthPrimeNumber = i
fmt.Println(primeCounter, "th prime number is ", nthPrimeNumber)
}
}
fmt.Println("第", number, "个素数是", nthPrimeNumber)
return nthPrimeNumber
}
英文:
Simple solution for generating prime numbers up to a certain limit:
func findNthPrime(number int) int {
if number < 1{
fmt.Println("Please provide positive number")
return number
}
var primeCounter, nthPrimeNumber int
for i:=2; primeCounter < number; i++{
isPrime := true
for j:=2; j <= int(math.Sqrt(float64(i))) && i != 2 ; j++{
if i % j == 0{
isPrime = false
}
}
if isPrime{
primeCounter++
nthPrimeNumber = i
fmt.Println(primeCounter, "th prime number is ", nthPrimeNumber)
}
}
fmt.Println("Nth prime number is ", nthPrimeNumber)
return nthPrimeNumber
}
答案11
得分: -1
质数是只能被1和自身整除的正整数。例如:2、3、5、7、11、13、17。
什么是质数?
质数是一个不能通过其他整数相乘得到的整数。
质数(或质数)是大于1且不是两个较小的自然数的乘积的自然数。大于1且不是质数的自然数被称为合数。
用Go语言编写的检查一个数是否为质数的程序
https://www.golanguagehub.com/2021/01/primenumber.html
英文:
A prime number is a positive integer that is divisible only by 1 and itself. For example: 2, 3, 5, 7, 11, 13, 17.
What is Prime Number?
A Prime Number is a whole number that cannot be made by multiplying other whole numbers
A prime number (or a prime) is a natural number greater than 1 that is not a product of two smaller natural numbers. A natural number greater than 1 that is not prime is called a composite number.
Go Language Program to Check Whether a Number is Prime or Not
https://www.golanguagehub.com/2021/01/primenumber.html
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