使用反射调用方法并返回值

huangapple go评论92阅读模式
英文:

Using reflection to call a method and return a value

问题

使用关于按名称调用方法的问题作为起点,我想通过名称调用一个方法,并实际对值进行操作。

package main

import "fmt"
import "reflect"

type T struct{}

func (t *T) Foo() {
	fmt.Println("foo")
}

type MyStruct struct {
	id int
}

type Person struct {
	Name string
	Age  int
}

func (t *T) Bar(ms *MyStruct, p *Person) int {
	return p.Age

}

func main() {
	var t *T
	reflect.ValueOf(t).MethodByName("Foo").Call([]reflect.Value{})
	var ans int
	ans = reflect.ValueOf(t).MethodByName("Bar").Call([]reflect.Value{reflect.ValueOf(&MyStruct{15}), reflect.ValueOf(&Person{"Dexter", 15})})
}

然而,我得到了以下错误:

prog.go:30: cannot use reflect.ValueOf(t).MethodByName("Bar").Call([]reflect.Value literal) (type []reflect.Value) as type int in assignment
 [process exited with non-zero status]

我应该如何改变代码才能实际返回一个值?我尝试使用类型转换并将其设置为int,但编译器说它不能是[]reflect.Value

英文:

Using the question about calling a method by name as a starting point, I wanted to call a method by name and actually do something with the value.

package main

import "fmt"
import "reflect"

type T struct{}

func (t *T) Foo() {
	fmt.Println("foo")
}

type MyStruct struct {
	id int
}

type Person struct {
	Name string
	Age  int
}

func (t *T) Bar(ms *MyStruct, p *Person) int {
	return p.Age

}

func main() {
	var t *T
	reflect.ValueOf(t).MethodByName("Foo").Call([]reflect.Value{})
	var ans int
	ans = reflect.ValueOf(t).MethodByName("Bar").Call([]reflect.Value{reflect.ValueOf(&MyStruct{15}), reflect.    ValueOf(&Person{"Dexter", 15})})
}

Playground link, http://play.golang.org/p/e02-KpdQ_P

However, I get the following error:

prog.go:30: cannot use reflect.ValueOf(t).MethodByName("Bar").Call([]reflect.Value literal) (type []reflect.Value) as type int in assignment
 [process exited with non-zero status] 

What should I do differently to actually return a value? I tried using type conversion and making it an int, but the compiler said that it couldn't []reflect.Value.
1: https://stackoverflow.com/questions/8103617/call-a-struct-and-its-method-by-name-in-go
2: http://play.golang.org/p/e02-KpdQ_P

答案1

得分: 3

Call返回的是一个[]reflect.Value,它是一个切片。你需要从切片中获取一个元素,以进行类型转换。一旦你有了一个reflect.Value实例,你可以调用Int()方法将其作为int64类型的值获取。

var ans int64
ans = reflect.ValueOf(t).MethodByName("Bar").Call([]reflect.Value{
    reflect.ValueOf(&MyStruct{15}), 
    reflect.ValueOf(&Person{"Dexter", 15})})[0].Int()
fmt.Println(ans)

Playground

英文:

Call returns []reflect.Value which is a slice. You need to get an element from the slice in order to do the type conversion. Once you have a reflect.Value instance you can call Int() to get the value as an int64.

var ans int64
ans = reflect.ValueOf(t).MethodByName("Bar").Call([]reflect.Value{
    reflect.ValueOf(&MyStruct{15}), 
    reflect.ValueOf(&Person{"Dexter", 15})})[0].Int()
fmt.Println(ans)

Playground

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  • 本文由 发表于 2014年2月6日 12:38:11
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