英文:
Custom MarshalJSON() never gets called in Go
问题
我已经写了自定义版本的MarshalJSON
和UnmarshalJSON
。我的UnmarshalJSON
按照我想要的方式被调用,但是我无法让它与MarshalJSON
一起工作。以下是总结我问题的代码:
package main
import (
"bytes"
"encoding/json"
"fmt"
"log"
"os"
)
type myStruct struct {
Data string `json:"data"`
}
func (s *myStruct) MarshalJSON() ([]byte, error) {
return []byte(`{"data":"charlie"}`), nil
}
func (s *myStruct) UnmarshalJSON(b []byte) error {
// 将字符串直接插入到Data成员中
return json.Unmarshal(b, &s.Data)
}
func main() {
// 创建一个初始内容为"alpha"的结构体
ms := myStruct{"alpha"}
// 使用自定义的UnmarshalJSON()将内容替换为"bravo"(成功)
if err := json.NewDecoder(bytes.NewBufferString(`"bravo"`)).Decode(&ms); err != nil {
log.Fatal(err)
}
// 使用自定义的MarshalJSON()获取"charlie"(不成功)
if err := json.NewEncoder(os.Stdout).Encode(ms); err != nil {
log.Fatal(err)
}
// 尝试另一种方法(不成功)
if ret, err := json.Marshal(ms); err != nil {
log.Fatal(err)
} else {
fmt.Println(string(ret))
}
// 验证Marshaler接口是否正确实现
var marsh json.Marshaler
marsh = &ms
ret, _ := marsh.MarshalJSON()
fmt.Println(string(ret)) // 输出"charlie"
}
简而言之,该程序以两种方式“自动”编码struct
,然后最后手动调用MarshalJSON
。我想要的结果是"charlie"
。运行代码会生成以下输出:
{"data":"bravo"}
{"data":"bravo"}
{"data":"charlie"}
你可以在Go Playground上尝试运行:http://play.golang.org/p/SJ05S8rAYN
英文:
I've written custom versions of MarshalJSON
and UnmarshalJSON
. My UnmarshalJSON
gets called the way I want it to, but I can't get it to work with MarshalJSON
. Here's code that summarizes my problem:
package main
import (
"bytes"
"encoding/json"
"fmt"
"log"
"os"
)
type myStruct struct {
Data string `json:"data"`
}
func (s *myStruct) MarshalJSON() ([]byte, error) {
return []byte(`{"data":"charlie"}`), nil
}
func (s *myStruct) UnmarshalJSON(b []byte) error {
// Insert the string directly into the Data member
return json.Unmarshal(b, &s.Data)
}
func main() {
// Create a struct with initial content "alpha"
ms := myStruct{"alpha"}
// Replace content with "bravo" using custom UnmarshalJSON() (SUCCESSFUL)
if err := json.NewDecoder(bytes.NewBufferString(`"bravo"`)).Decode(&ms); err != nil {
log.Fatal(err)
}
// Use custom MarshalJSON() to get "charlie" back (UNSUCCESSFUL)
if err := json.NewEncoder(os.Stdout).Encode(ms); err != nil {
log.Fatal(err)
}
// Trying another method (UNSUCCESSFUL)
if ret, err := json.Marshal(ms); err != nil {
log.Fatal(err)
} else {
fmt.Println(string(ret))
}
// Verify that the Marshaler interface is correctly implemented
var marsh json.Marshaler
marsh = &ms
ret, _ := marsh.MarshalJSON()
fmt.Println(string(ret)) // Prints "charlie"
}
In short, the program encodes the struct
"automatically" in two ways, and then finally calls MarshalJSON
manually. The response I want is "charlie"
. Running the code generates the following output:
{"data":"bravo"}
{"data":"bravo"}
{"data":"charlie"}
Try it at Go Playground: http://play.golang.org/p/SJ05S8rAYN
答案1
得分: 49
在代码的这部分中,ms
被复制到一个interface{}
变量中:
// 尝试另一种方法(不成功)
if ret, err := json.Marshal(ms); err != nil {
问题在于,这个变量没有实现json.Marshaler
接口,因为MarshalJSON
不在myStruct
的方法集中(只在*myStruct
中)。
修复的方法要么是(a)使你的MarshalJSON
方法接受一个非指针接收器(这意味着它会得到结构体的副本:如果结构体很大可能会很耗费资源),要么是(b)将结构体的指针进行编组(正如Kavu在评论中提到的)。
这种行为的原因是,Go语言不允许你获取存储在接口变量中的值的指针,而是要求你在每次访问它时都要复制该值。虽然语言提供了语法糖将ms.MarshalJSON()
转换为(&ms).MarshalJSON()
以通过指针接收器访问方法,但对于存储在接口变量中的值来说,这是不可能的。因此,该方法不被认为是其方法集的一部分。
英文:
In this part of the code, ms
gets copied into an interface{}
variable:
// Trying another method (UNSUCCESSFUL)
if ret, err := json.Marshal(ms); err != nil {
The problem is that this variable does not implement the json.Marshaler
interface, since MarshalJSON
is not in the method set for myStruct
(only for *myStruct
).
The fix is to either (a) make your MarshalJSON
method take a non-pointer receiver (which will mean it gets a copy of the struct: possibly costly if it is large), or (b) marshal a pointer to the struct (as Kavu mentioned in a comment).
The reason for this behaviour is that Go doesn't let you take a pointer to the value stored inside an interface variable, instead requiring you to make a copy of the value whenever you want to access it. While the language has syntactic sugar to convert ms.MarshalJSON()
into (&ms).MarshalJSON()
as a way to access the method with a pointer receiver, this can not be done for a value stored in an interface variable. For this reason, the method is not considered to be in its method set.
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