英文:
How to set Content-Type for a form filed using 'multipart' in Go
问题
我正在尝试上传一个文件,需要为API设置特定的Content-Type。当我这样做时:
file, err := os.Open("helloWorld.wav")
buf := new(bytes.Buffer)
writer := multipart.NewWriter(buf)
audioFile, _ := writer.CreateFormFile("file", "helloWorld.wav")
_, err = io.Copy(audioFile, file)
if err != nil {
return nil, 0, err
}
writer.Close()
它正确地创建了multipart表单,但是假设了这个内容类型:
Content-Type: application/octet-stream
我需要能够将其设置为:
Content-Type: audio/wav;rate=8000
当然,我可以为net/http设置头部,但是我不知道如何为multipart表单中的单个字段设置头部。
英文:
I am attempting to upload a file that requires me to set a specific Content-Type for the API. When I do this:
file, err := os.Open("helloWorld.wav")
buf := new(bytes.Buffer)
writer := multipart.NewWriter(buf)
audioFile, _ := writer.CreateFormFile("file", "helloWorld.wav")
_, err = io.Copy(audioFile, file)
if err != nil {
return nil, 0, err
}
writer.Close()
It creates the multipart form properly, but assumes this content type:
Content-Type: application/octet-stream
I need to be able to set it to:
Content-Type: audio/wav;rate=8000
While of course I may set the headers for net/http, I am not seeing how to do this for individual fields in a multipart form.
答案1
得分: 18
查看源代码mime/multipart,似乎不可能实现,但你可以实现类似的功能(注意:它没有正确处理文件名的转义)。
func CreateAudioFormFile(w *multipart.Writer, filename string) (io.Writer, error) {
h := make(textproto.MIMEHeader)
h.Set("Content-Disposition", fmt.Sprintf(`form-data; name="%s"; filename="%s"`, "file", filename))
h.Set("Content-Type", "audio/wav;rate=8000")
return w.CreatePart(h)
}
输出结果:
--0c4c6b408a5a8bf7a37060e54f4febd6083fd6758fd4b3975c4e2ea93732
Content-Disposition: form-data; name="file"; filename="helloWorld.wav"
Content-Type: audio/wav;rate=8000
--0c4c6b408a5a8bf7a37060e54f4febd6083fd6758fd4b3975c4e2ea93732--
完整示例请参见playground。
编辑:要写入文件数据,也将其复制到写入器中,就像原始示例中一样。
audioFile, _ := CreateAudioFormFile(writer2, "helloWorld.wav")
io.Copy(audioFile, file)
包含文件数据的完整示例请参见更新的playground。
英文:
Looking at the source code mime/multipart it's not possible, but you could implement something like this (note: it's not handling the escaping of filename correctly)
func CreateAudioFormFile(w *multipart.Writer, filename string) (io.Writer, error) {
h := make(textproto.MIMEHeader)
h.Set("Content-Disposition", fmt.Sprintf(`form-data; name="%s"; filename="%s"`, "file", filename))
h.Set("Content-Type", "audio/wav;rate=8000")
return w.CreatePart(h)
}
Outputs
>
--0c4c6b408a5a8bf7a37060e54f4febd6083fd6758fd4b3975c4e2ea93732
Content-Disposition: form-data; name="file"; filename="helloWorld.wav"
Content-Type: audio/wav;rate=8000
--0c4c6b408a5a8bf7a37060e54f4febd6083fd6758fd4b3975c4e2ea93732--
See playground for full example.
Edit: To write the file data, also copy it to the writer as in the original example.
audioFile, _ := CreateAudioFormFile(writer2, "helloWorld.wav")
io.Copy(audioFile, file)
See updated playground for the full example that includes the file data.
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库,让每个人都能够通过互相帮助和分享经验来进步。
评论