英文:
Easy way to get the keys in a map in alphabetical order
问题
在Go语言中，按字母顺序获取映射中的键的最简单方法是什么？这是我能做到的最简短的方法：
package main
import "container/vector"
import "fmt"
import "sort"
func main() {
m := map[string]string {"b":"15", "z":"123123", "x":"sdf", "a":"12"}
var keys vector.StringVector;
for k,_ := range ( m ) {
keys.Push(k)
}
sort.Sort( &keys )
fmt.Printf("%v\n", keys)
}
请注意，这是一个Go语言代码示例，用于按字母顺序获取映射中的键，并打印排序后的结果。
英文:
In Go, what's the easiest way to get the keys in a map sorted alphabetically? This is the shortest way I can do it:
package main
import "container/vector"
import "fmt"
import "sort"
func main() {
m := map[string]string {"b":"15", "z":"123123", "x":"sdf", "a":"12"}
var keys vector.StringVector;
for k,_ := range ( m ) {
keys.Push(k)
}
sort.Sort( &keys )
fmt.Printf("%v\n", keys)
}
答案1
得分: 57
你正在使用StringVector对字符串数组进行排序。为了最小化开销，你可以对字符串数组进行排序。
package main
import (
"fmt"
"sort"
)
func main() {
m := map[string]string{"b": "15", "z": "123123", "x": "sdf", "a": "12"}
mk := make([]string, len(m))
i := 0
for k, _ := range m {
mk[i] = k
i++
}
sort.Strings(mk)
fmt.Println(mk)
}
输出：
[a b x z]
英文:
You are sorting an array of strings using StringVector. To minimize overhead, you could sort an array of strings.
package main
import (
"fmt"
"sort"
)
func main() {
m := map[string]string{"b": "15", "z": "123123", "x": "sdf", "a": "12"}
mk := make([]string, len(m))
i := 0
for k, _ := range m {
mk[i] = k
i++
}
sort.Strings(mk)
fmt.Println(mk)
}
Output:
[a b x z]
答案2
得分: 17
那将是最优雅的方法：
package main
import (
"fmt"
"sort"
)
func main() {
m := map[string]string{"b": "15", "z": "123123", "x": "sdf", "a": "12"}
keys := make([]string, 0, len(m))
for key := range m {
keys = append(keys, key)
}
sort.Strings(keys)
fmt.Println(keys)
}
英文:
That would be most elegant method:
package main
import (
"fmt"
"sort"
)
func main() {
m := map[string]string{"b": "15", "z": "123123", "x": "sdf", "a": "12"}
keys := make([]string, 0, len(m))
for key := range m {
keys = append(keys, key)
}
sort.Strings(keys)
fmt.Println(keys)
}
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