英文:
How to convert uint8 to string
问题
我想将uint8转换为字符串，但是无法弄清楚如何做。
package main
import "fmt"
import "strconv"
func main() {
str := "Hello"
fmt.Println(str[1]) // 101
fmt.Println(strconv.Itoa(int(str[1])))
}
这给出了prog.go:11: cannot use str[1] (type uint8) as type int in function argument [process exited with non-zero status]。
有什么想法吗？
英文:
I want to convert uint8 to string but can't figure out how.
package main
import "fmt"
import "strconv"
func main() {
str := "Hello"
fmt.Println(str[1]) // 101
fmt.Println(strconv.Itoa(str[1]))
}
This gives me prog.go:11: cannot use str[1] (type uint8) as type int in function argument
[process exited with non-zero status]
Any idea?
答案1
得分: 31
只需将其转换为：
fmt.Println(strconv.Itoa(int(str[1])))
答案2
得分: 11
在转换或强制转换之间存在差异，请考虑以下代码：
var s uint8 = 10
fmt.Print(string(s))
fmt.Print(strconv.Itoa(int(s)))
字符串强制转换打印出'\n'（换行符），而字符串转换打印出"10"。一旦你考虑到两种变体的[]byte转换，差异就变得清楚了：
[]byte(string(s)) == [10] // 由10表示的单个字符
[]byte(strconv.Itoa(int(s))) == [49, 48] // '1'和'0'的字符编码
你可以在play.golang.org上查看这段代码：点击这里
英文:
There is a difference between converting it or casting it, consider:
var s uint8 = 10
fmt.Print(string(s))
fmt.Print(strconv.Itoa(int(s)))
The string cast prints '\n' (newline), the string conversion prints "10". The difference becomes clear once you regard the []byte conversion of both variants:
[]byte(string(s)) == [10] // the single character represented by 10
[]byte(strconv.Itoa(int(s))) == [49, 48] // character encoding for '1' and '0'
<iframe src="http://play.golang.org/p/kek9D7ol22" frameborder="0" style="width: 100%; height: 100%"><a href="http://play.golang.org/p/kek9D7ol22">see this code in play.golang.org</a></iframe>
答案3
得分: 7
你可以通过使用类型转换来更简单地完成，这对我有效：
var c uint8
c = 't'
fmt.Printf(string(c))
英文:
You can do it even simpler by using casting, this worked for me:
var c uint8
c = 't'
fmt.Printf(string(c))
答案4
得分: 0
在Go表达式中，基本类型没有自动转换。请参阅https://talks.golang.org/2012/goforc.slide#18。byte（uint8的别名）或[]byte（[]uint8）必须设置为bool、数字或字符串。
package main
import (
. "fmt"
)
func main() {
b := []byte{'G', 'o'}
c := []interface{}{b[0], float64(b[0]), int(b[0]), rune(b[0]), string(b[0]), Sprintf("%s", b), b[0] != 0}
checkType(c)
}
func checkType(s []interface{}) {
for k, _ := range s {
// uint8 71, float64 71, int 71, int32 71, string G, string Go, bool true
Printf("%T %v\n", s[k], s[k])
}
}
Sprintf("%s", b)可以将[]byte{'G', 'o'}转换为字符串"Go"。您可以使用Sprintf将任何int类型转换为字符串。请参阅https://stackoverflow.com/a/41074199/12817546。
但是，Sprintf使用了反射。请参阅https://stackoverflow.com/a/22626531/12817546中的注释。使用Itoa（整数转ASCII）更快。请参阅@DenysSéguret和https://stackoverflow.com/a/38077508/12817546。引号已编辑。
英文:
There are no automatic conversions of basic types in Go expressions. See https://talks.golang.org/2012/goforc.slide#18. A byte (an alias of uint8) or []byte ([]uint8) has to be set to a bool, number or string.
package main
import (
. "fmt"
)
func main() {
b := []byte{'G', 'o'}
c := []interface{}{b[0], float64(b[0]), int(b[0]), rune(b[0]), string(b[0]), Sprintf("%s", b), b[0] != 0}
checkType(c)
}
func checkType(s []interface{}) {
for k, _ := range s {
// uint8 71, float64 71, int 71, int32 71, string G, string Go, bool true
Printf("%T %v\n", s[k], s[k])
}
}
Sprintf("%s", b) can be used to convert []byte{'G', 'o' } to the string "Go". You can convert any int type to a string with Sprintf. See https://stackoverflow.com/a/41074199/12817546.
But Sprintf uses reflection. See the comment in https://stackoverflow.com/a/22626531/12817546. Using Itoa (Integer to ASCII) is faster. See @DenysSéguret and https://stackoverflow.com/a/38077508/12817546. Quotes edited.
答案5
得分: -1
使用%c
str := "Hello"
fmt.Println(str[1]) // 101
fmt.Printf("%c\n", str[1])
使用%c可以将整数值解释为对应的Unicode字符。在上面的示例中，str[1]的值为101，对应的Unicode字符是'e'。因此，fmt.Printf("%c\n", str[1])会输出'e'。
英文:
use %c
str := "Hello"
fmt.Println(str[1]) // 101
fmt.Printf("%c\n", str[1])
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