英文:
Go, regexp : to match either case and keep the original text
问题
我想用新的字符串替换与正则表达式匹配的字符串，但仍然保留原始文本的一部分。
我想要得到：
I own_VERB it and also have_VERB it
从
I own it and also have it
我该如何用一行代码实现这个？我尝试过，但无法进一步。谢谢。
package mainimport "fmt"import "regexp"func getverb(str string) string {var validID = regexp.MustCompile(`(own)|(have)`)return validID.ReplaceAllString(str, "_VERB")}func main() {fmt.Println(getverb("I own it and also have it"))// 如何保留原始文本，例如// I own_VERB it and also have_VERB it}
英文:
I want to replace regex-matched strings with new string but still keeping part of the original text.
I want to get
I own_VERB it and also have_VERB it
from
I own it and also have it
how do I do this with one line of code? I tried but can't get further than this. Thanks,
http://play.golang.org/p/SruLyf3VK_
package mainimport "fmt"import "regexp"func getverb(str string) string {var validID = regexp.MustCompile(`(own)|(have)`)return validID. ReplaceAllString(str, "_VERB")}func main() {fmt.Println(getverb("I own it and also have it"))// how do I keep the original text like// I own_VERB it and also have_VERB it}
答案1
得分: 3
你甚至不需要为此使用捕获组。
package mainimport "fmt"import "regexp"func getverb(str string) string {var validID = regexp.MustCompile(`own|have`)return validID.ReplaceAllString(str, "package mainimport "fmt"import "regexp"func getverb(str string) string {var validID = regexp.MustCompile(`own|have`)return validID.ReplaceAllString(str, "${0}_VERB")}func main() {fmt.Println(getverb("I own it and also have it"))// 如何保留原始文本，例如// I own_VERB it and also have_VERB it}_VERB")}func main() {fmt.Println(getverb("I own it and also have it"))// 如何保留原始文本，例如// I own_VERB it and also have_VERB it}
${0} 包含与整个模式匹配的字符串；${1} 将包含与第一个子模式（或捕获组）匹配的字符串（如果有的话），你可以在 Darka 的回答中看到。
英文:
You don't even need a capture group for this.
package mainimport "fmt"import "regexp"func getverb(str string) string {var validID = regexp.MustCompile(`own|have`)return validID. ReplaceAllString(str, "package mainimport "fmt"import "regexp"func getverb(str string) string {var validID = regexp.MustCompile(`own|have`)return validID. ReplaceAllString(str, "${0}_VERB")}func main() {fmt.Println(getverb("I own it and also have it"))// how do I keep the original text like// I own_VERB it and also have_VERB it}_VERB")}func main() {fmt.Println(getverb("I own it and also have it"))// how do I keep the original text like// I own_VERB it and also have_VERB it}
${0} contains the string which matched the whole pattern; ${1} will contain the string which matched the first sub-pattern (or capture group) if there is any, and which you can see in Darka's answer.
答案2
得分: 1
在替换过程中，$符号的解释与Expand中的解释相同，因此例如$1表示第一个子匹配的文本。
package mainimport ("fmt""regexp")func main() {re := regexp.MustCompile("(own|have)")fmt.Println(re.ReplaceAllString("I own it and also have it", "_VERB"))}
输出结果：
I own_VERB it and also have_VERB it
英文:
>Inside replacement, $ signs are interpreted as in Expand, so for instance $1 represents the text of the first submatch.
package mainimport ("fmt""regexp")func main() {re := regexp.MustCompile("(own|have)")fmt.Println(re.ReplaceAllString("I own it and also have it", "_VERB"))}
Output
I own_VERB it and also have_VERB it
答案3
得分: 1
似乎需要进行一些谷歌搜索：
var validID = regexp.MustCompile(`(own|have)`)return validID.ReplaceAllString(str, "_VERB")
这段代码的作用是将字符串中的 "own" 或者 "have" 替换为 "${1}_VERB"。
英文:
Seems a bit googling helps:
var validID = regexp.MustCompile(`(own|have)`)return validID. ReplaceAllString(str, "_VERB")
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