英文:
Parsing Perl regex with golang
问题
这是我的代码和代码示例。
func insert_comma(input_num int) string {temp_str := strconv.Itoa(input_num)var validID = regexp.MustCompile(`\B(?=(\d{3})+$)`)return validID.ReplaceAllString(temp_str, ",")}func main() {fmt.Println(insert_comma(1000000000))}
基本上，我想要的输入是 1,000,000,000。
这个正则表达式在JavaScript中有效，但我不知道如何在Go中使用这个Perl正则表达式。非常感谢。谢谢！
英文:
http://play.golang.org/p/GM0SWo0qGs
This is my code and playground.
func insert_comma(input_num int) string {temp_str := strconv.Itoa(input_num)var validID = regexp.MustCompile(`\B(?=(\d{3})+$)`)return validID.ReplaceAllString(temp_str, ",")}func main() {fmt.Println(insert_comma(1000000000))}
Basically, my desired input is 1,000,000,000.
And the regular expression works in Javascript but I do not know how to make this Perl regex work in Go. I would greatly appreciate it. Thanks,
答案1
得分: 2
由于前瞻断言似乎不被支持，我为您提供了一种不使用正则表达式的不同算法：
Perl 代码：
sub insert_comma {my $x=shift;my $l=length($x);for (my $i=$l%3==0?3:$l%3;$i<$l;$i+=3) {substr($x,$i++,0)=',';}return $x;}print insert_comma(1000000000);
Go 代码：免责声明：我对 Go 语言没有任何经验，所以如果有错误，请谅解并随意编辑我的帖子！
func insert_comma(input_num int) string {temp_str := strconv.Itoa(input_num)var result []stringi := len(temp_str)%3;if i == 0 { i = 3 }for index,element := range strings.Split(temp_str, "") {if i == index {result = append(result, ",");i += 3;}result = append(result, element)}return strings.Join(result, "")}func main() {fmt.Println(insert_comma(1000000000))}
您可以在此链接中查看运行结果：http://play.golang.org/p/7pvo7-3G-s
英文:
Since lookahead assertion seems to be not supported, I'm providing you a different algorithm with no regexp:
Perl code:
sub insert_comma {my $x=shift;my $l=length($x);for (my $i=$l%3==0?3:$l%3;$i<$l;$i+=3) {substr($x,$i++,0)=',';}return $x;}print insert_comma(1000000000);
Go code: Disclaimer: I have zero experience with Go, so bear with me if I have errors and feel free to edit my post!
func insert_comma(input_num int) string {temp_str := strconv.Itoa(input_num)var result []stringi := len(temp_str)%3;if i == 0 { i = 3 }for index,element := range strings.Split(temp_str, "") {if i == index {result = append(result, ",");i += 3;}result = append(result, element)}return strings.Join(result, "")}func main() {fmt.Println(insert_comma(1000000000))}
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