英文:
Go - trying to create a .pgm file but end up with a binary file
问题
我正在阅读一个pgm文件，以便对其应用一些滤镜，并将结果重写到一个新的pgm文件中。然而，我总是得到一个二进制文件（vim不显示数值，而是显示^G ^0 ^K等字符，file命令告诉我这是一个数据文件，imagemagick无法打开该文件）。
我写入文件的代码如下：
fd,err := os.Create(filename)
wr := bufio.NewWriter(fd)
//img是一个[][]int类型的变量，保存要写入的数值
str := "P2\n" + filename + "\n" + string(len(img[0])) + ...
if _,err := wr.WriteString(outStr); err != nil {..}
然后在一个循环中，我遍历img数组执行类似的操作。
我在这里漏掉了什么？
英文:
I'm reading a pgm-file in order to apply some filter to it and rewrite the result to a new pgm-file. However, I always end up with a binary file (vim doesn't show the values but stuff like ^G ^0 ^K etc, the file-command tells me it's a data file and imagemagick can't open the file)
The code where I write to the file looks like this:
fd,err := os.Create(filename)
wr := bufio.NewWriter(fd)
//img is of type [][]int and holds the values to be written
str := "P2\n" + filename + "\n" + string(len(img[0])) + ...
if _,err := wr.WriteString(outStr); err != nil {..}
and then some more of that in a loop where I go through the img array.
What am I missing here?
答案1
得分: 4
string(len(img[0]))在这里并不是你想要的操作。你需要使用strconv.Itoa。
string(len(img[0]))会创建一个只包含Unicode码点为len(img[0])的字符的单个字符字符串（参见规范中的转换部分）。
英文:
string(len(img[0])) doesn't do what you're trying to do here. You need strconv.Itoa
string(len(img[0])) is creating a single character string containing whichever character is the Unicode code point for len(img[0]) (see the spec section on conversions)
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论