英文:
Idiomatic way to use strconv.ParseInt with ints
问题
我最终写出了这样的代码。我需要一个普通的int（用于其他函数调用），但是parseInt只能产生64位的int：
i64, err := strconv.ParseInt(s, 10, 0)if err != nil {fmt.Println("解析失败：", s)}i := int(i64)
http://play.golang.org/p/_efRm7yp3o
有没有办法避免额外的类型转换？或者有没有办法使这个代码更符合惯用写法？
英文:
I end up writing code like this. I need a regular int (for some other function call), but parseInt only produces 64 bit ints:
i64, err := strconv.ParseInt(s, 10, 0)if err != nil {fmt.Println("parsing failed for", s)}i := int(i64)
http://play.golang.org/p/_efRm7yp3o
Is there a way to avoid the extra cast? Or a way to make this more idiomatic?
答案1
得分: 3
你可以使用strconv.Atoi，它以你想要的方式包装了strconv.ParseInt。
英文:
You can use strconv.Atoi which wraps strconv.ParseInt in a way you want.
答案2
得分: 0
使用strconv.ParseInt的bitSize参数。
package mainimport ("fmt""strconv")// 32或64，取决于平台const IntBits = 1 << (^uint(0)>>32&1 + ^uint(0)>>16&1 + ^uint(0)>>8&1 + 3)func printInt(i int) {fmt.Println(i)}func main() {s := "-123123112323231231"i64, err := strconv.ParseInt(s, 10, IntBits)if err != nil {fmt.Println("解析失败：", s)}i := int(i64)printInt(i)i64, err = strconv.ParseInt(s, 10, 32)if err != nil {fmt.Println("解析失败：", s)}i = int(i64)printInt(i)}
输出
-123123112323231231解析失败： -123123112323231231-2147483648
英文:
Use the bitSize parameter of strconv.ParseInt
package mainimport ("fmt""strconv")// 32 or 64 depending on platformconst IntBits = 1 << (^uint(0)>>32&1 + ^uint(0)>>16&1 + ^uint(0)>>8&1 + 3)func printInt(i int) {fmt.Println(i)}func main() {s := "-123123112323231231"i64, err := strconv.ParseInt(s, 10, IntBits)if err != nil {fmt.Println("parsing failed for ", s)}i := int(i64)printInt(i)i64, err = strconv.ParseInt(s, 10, 32)if err != nil {fmt.Println("parsing failed for ", s)}i = int(i64)printInt(i)}
Output
-123123112323231231parsing failed for -123123112323231231-2147483648
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