英文:
Go Tour basics #13: how come there's no overflow?
问题
在Go Tour的基础知识，切片＃13中，呈现了以下内容：
MaxInt uint64 = 1<<64 - 1
当运行示例时，它的计算结果是正确的；我只是无法理解为什么。
unit64是我所了解的Go中int的最大容器。
同时，当在表达式中使用1<<64（例如在fmt.Printf(1<<64)中）时，它会导致异常 - 也就是说，它不像其他几种编程语言中的0。
然而，当在赋值运算符的右侧使用时，它的计算结果是正确的。
我在这里漏掉了什么？
英文:
In the Go Tour basics, slice #13, the following is presented:
MaxInt uint64 = 1<<64 - 1
It evaluates correctly as seen when the example gets run; I just can't seem to understand why.
unit64 is the biggest container for an int in Go as far as I understand.
At the same time 1<<64 evaluates to an exception when used in an expression (such as in fmt.Printf(1<<64)) - that is, it's not 0 as in several other programming languages.
Still, when used on the right side of the assignment operator it evaluates fine.
What am I missing here?
答案1
得分: 1
不要紧，幻灯片＃15似乎解释了它：它是一个常量，因此“没有限制的大小”（至少不是64位）。我觉得这很奇怪，但作为解释来说还可以接受。
英文:
Never mind, slide #15 seems to explain it: it's a constant and as such "does not have limited size" (not to 64 bits anyway). I feel it strange but it's OK for an explanation.
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