英文:
Reading from serial port with while-loop
问题
我用Go语言编写了一个简短的程序,通过串口与传感器进行通信:
package main
import (
"fmt"
"github.com/tarm/goserial"
"time"
)
func main() {
c := &serial.Config{Name: "/dev/ttyUSB0", Baud: 9600}
s, err := serial.OpenPort(c)
if err != nil {
fmt.Println(err)
}
_, err = s.Write([]byte("\x16\x02N0C0 G A\x03\x0d\x0a"))
if err != nil {
fmt.Println(err)
}
time.Sleep(time.Second/2)
buf := make([]byte, 40)
n, err := s.Read(buf)
if err != nil {
fmt.Println(err)
}
fmt.Println(string(buf[:n]))
s.Close()
}
它工作得很好,但在写入端口后,我必须等待大约半秒钟才能开始读取。我想使用while循环而不是time.Sleep
来读取所有传入的数据。我的尝试不起作用:
buf := make([]byte, 40)
n := 0
for {
n, _ := s.Read(buf)
if n > 0 {
break
}
}
fmt.Println(string(buf[:n]))
我猜每次循环通过后,buf
都会被覆盖。有什么建议吗?
英文:
I’ve written a short program in Go to communicate with a sensor through a serial port:
package main
import (
"fmt"
"github.com/tarm/goserial"
"time"
)
func main() {
c := &serial.Config{Name: "/dev/ttyUSB0", Baud: 9600}
s, err := serial.OpenPort(c)
if err != nil {
fmt.Println(err)
}
_, err = s.Write([]byte("\x16\x02N0C0 G A\x03\x0d\x0a"))
if err != nil {
fmt.Println(err)
}
time.Sleep(time.Second/2)
buf := make([]byte, 40)
n, err := s.Read(buf)
if err != nil {
fmt.Println(err)
}
fmt.Println(string(buf[:n]))
s.Close()
}
It works fine, but after writing to the port I have to wait about half a second before I can start reading from it. I would like to use a while-loop instead of time.Sleep
to read all incoming data. My attempt doesn’t work:
buf := make([]byte, 40)
n := 0
for {
n, _ := s.Read(buf)
if n > 0 {
break
}
}
fmt.Println(string(buf[:n]))
I guess buf
gets overwritten after every loop pass. Any suggestions?
答案1
得分: 11
你的问题是Read()
会在有一些数据时返回,它不会等待所有的数据。请参考io.Reader规范获取更多信息。
你想要做的是读取直到达到某个分隔符。我不知道你尝试使用的确切格式,但看起来可能\x0a
是结束分隔符。
在这种情况下,你可以使用bufio.Reader,像这样:
reader := bufio.NewReader(s)
reply, err := reader.ReadBytes('\x0a')
if err != nil {
panic(err)
}
fmt.Println(reply)
这将读取数据直到第一个\x0a
。
英文:
Your problem is that Read()
will return whenever it has some data - it won't wait for all the data. See the io.Reader specification for more info
What you want to do is read until you reach some delimiter. I don't know exactly what format you are trying to use, but it looks like maybe \x0a
is the end delimiter.
In which case you would use a bufio.Reader like this
reader := bufio.NewReader(s)
reply, err := reader.ReadBytes('\x0a')
if err != nil {
panic(err)
}
fmt.Println(reply)
Which will read data until the first \x0a
.
答案2
得分: 1
是的,每次调用Read()
时,buf
都会被覆盖。
我会采用在文件句柄上设置超时的方法。
s, _ := os.OpenFile("/dev/ttyS0", syscall.O_RDWR|syscall.O_NOCTTY|syscall.O_NONBLOCK, 0666)
t := syscall.Termios{
Iflag: syscall.IGNPAR,
Cflag: syscall.CS8 | syscall.CREAD | syscall.CLOCAL | syscall.B115200,
Cc: [32]uint8{syscall.VMIN: 0, syscall.VTIME: uint8(20)}, //2.0s timeout
Ispeed: syscall.B115200,
Ospeed: syscall.B115200,
}
// syscall
syscall.Syscall6(syscall.SYS_IOCTL, uintptr(s.Fd()),
uintptr(syscall.TCSETS), uintptr(unsafe.Pointer(&t)),
0, 0, 0)
// 发送消息
n, _ := s.Write([]byte("Test message"))
// 接收回复
for {
buf := make([]byte, 128)
n, err = s.Read(buf)
if err != nil { // err will equal io.EOF
break
}
fmt.Printf("%v\n", string(buf))
}
另外请注意,如果没有更多数据可读且没有错误,os.File.Read()
将返回io.EOF
的错误,
你可以在这里看到。
英文:
> I guess buf gets overwritten after every loop pass. Any suggestions?
Yes, buf
will get overwritten with every call to Read()
.
A timeout on the file handle would be the approach I would take.
s, _ := os.OpenFile("/dev/ttyS0", syscall.O_RDWR|syscall.O_NOCTTY|syscall.O_NONBLOCK, 0666)
t := syscall.Termios{
Iflag: syscall.IGNPAR,
Cflag: syscall.CS8 | syscall.CREAD | syscall.CLOCAL | syscall.B115200,
Cc: [32]uint8{syscall.VMIN: 0, syscall.VTIME: uint8(20)}, //2.0s timeout
Ispeed: syscall.B115200,
Ospeed: syscall.B115200,
}
// syscall
syscall.Syscall6(syscall.SYS_IOCTL, uintptr(s.Fd()),
uintptr(syscall.TCSETS), uintptr(unsafe.Pointer(&t)),
0, 0, 0)
// Send message
n, _ := s.Write([]byte("Test message"))
// Receive reply
for {
buf := make([]byte, 128)
n, err = s.Read(buf)
if err != nil { // err will equal io.EOF
break
}
fmt.Printf("%v\n", string(buf))
}
Also note, if there is no more data read and there is no error, os.File.Read() will return an error of io.EOF
,
as you can see here.
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