英文:
List comprehension in Go
问题
我有一个结构体数组。
var a = [] struct {
f1 string
f2 string
}{
{"foo", "bar"},
{"biz", "baz"},
}
我想将f2字段的数组传递给一个函数，像这样
var f2s []string
for _, s := range a {
f2s = append(f2s, s.f2)
}
// f2s = {"bar", "baz"}
SomeFunc(f2s)
有没有更符合惯用方式的方法来做到这一点？在Python中，我会这样做SomeFunc([s.f2 for s in a])。在函数式语言中，我会这样做(SomeFunc (map (lambda (s) (s.f2)) a))。
英文:
I have an array of structs.
var a = [] struct {
f1 string
f2 string
}{
{"foo", "bar"},
{"biz", "baz"},
}
I want to pass an array of the f2 fields to a function, like so
var f2s []string
for _, s := range a {
f2s = append.f2s(s.f2)
}
// f2s = {"bar", "baz"}
SomeFunc(f2s)
Is there a more idiomatic way to do this? In Python I would do SomeFunc([s.f2 for s in a]). In a functional language I would do (SomeFunc (map (lambda (s) (s.f2)) a)).
答案1
得分: 11
不，Go语言没有列表强制转换或类似的功能。你的代码看起来很好。对于较长的切片，最好使用make函数来分配适当的长度。
英文:
No, Go has no list coercion or that like. Your code looks fine. For longer slices it might be better to allocate the proper length with make.
答案2
得分: 7
不，真诚地说，他们不会。
地图和列表的理解已经足够主流，被认为是任何现代语言中的基础。
这是一种很好的语言，有很多好的想法，但我离感到舒适还有很长的路要走，而且经常感觉我的代码很脏，即使它是按照Go的方式进行的，结构良好的代码。
希望将来会有所改变。
英文:
No, sincerely, they wouldn't.
Maps and lists comprehension is mainstream enough to be considered basic in any modern language.
It's a nice language with great ideas, but I'm still way far from being comfortable, and often times I feel my code is dirty even when it is idiomatic, well structured code in the Go way of doing things.
Hope this changes in the future.
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