英文:
How do you replace a character in Go using the Regexp package ReplaceAll function?
问题
我不熟悉类C语法,并且想要编写代码来查找和替换源字符串中的所有'A'为'B',例如使用Regexp包的ReplaceAll或ReplaceAllString函数。我该如何设置类型Regexp、src和repl?这是来自Go文档的ReplaceAll代码片段:
// ReplaceAll返回src的副本,其中所有与Regexp匹配的内容都被repl替换。不支持在替换文本中使用表达式(例如\1或$1)。
func (re *Regexp) ReplaceAll(src, repl []byte) []byte {
lastMatchEnd := 0; // 最近匹配的结束位置
searchPos := 0; // 下一次查找匹配的位置
buf := new(bytes.Buffer);
for searchPos <= len(src) {
a := re.doExecute("", src, searchPos);
if len(a) == 0 {
break // 没有更多匹配
}
// 复制此匹配之前的未匹配字符。
buf.Write(src[lastMatchEnd:a[0]]);
// 现在插入替换字符串的副本,但不适用于紧接在另一个匹配之后的空字符串的匹配。
// (否则,对于同时匹配空字符串和非空字符串的模式,我们会得到双重替换。)
if a[1] > lastMatchEnd || a[0] == 0 {
buf.Write(repl)
}
lastMatchEnd = a[1];
// 推进到此匹配之后;始终至少推进一个字符。
_, width := utf8.DecodeRune(src[searchPos:len(src)]);
if searchPos+width > a[1] {
searchPos += width
} else if searchPos+1 > a[1] {
// 仅在输入字符串的末尾需要此子句。在这种情况下,DecodeRuneInString返回width=0。
searchPos++
} else {
searchPos = a[1]
}
}
// 复制最后一个匹配之后的未匹配字符。
buf.Write(src[lastMatchEnd:len(src)]);
return buf.Bytes();
}
英文:
I am not familiar with C-like syntaxes and would like to write code to find & replace, say, all 'A's to 'B's in a source string, say 'ABBA' with the Regexp package ReplaceAll or ReplaceAllString functions? How do I set up type Regexp, src and repl? Here's the ReplaceAll code snippet from the Go documentation:
<pre>// ReplaceAll returns a copy of src in which all matches for the Regexp
// have been replaced by repl. No support is provided for expressions
// (e.g. \1 or $1) in the replacement text.
func (re *Regexp) ReplaceAll(src, repl []byte) []byte {
lastMatchEnd := 0; // end position of the most recent match
searchPos := 0; // position where we next look for a match
buf := new(bytes.Buffer);
for searchPos <= len(src) {
a := re.doExecute("", src, searchPos);
if len(a) == 0 {
break // no more matches
}
// Copy the unmatched characters before this match.
buf.Write(src[lastMatchEnd:a[0]]);
// Now insert a copy of the replacement string, but not for a
// match of the empty string immediately after another match.
// (Otherwise, we get double replacement for patterns that
// match both empty and nonempty strings.)
if a[1] > lastMatchEnd || a[0] == 0 {
buf.Write(repl)
}
lastMatchEnd = a[1];
// Advance past this match; always advance at least one character.
_, width := utf8.DecodeRune(src[searchPos:len(src)]);
if searchPos+width > a[1] {
searchPos += width
} else if searchPos+1 > a[1] {
// This clause is only needed at the end of the input
// string. In that case, DecodeRuneInString returns width=0.
searchPos++
} else {
searchPos = a[1]
}
}
// Copy the unmatched characters after the last match.
buf.Write(src[lastMatchEnd:len(src)]);
return buf.Bytes();
}
<code>
答案1
得分: 4
这是一个执行你想要的操作的例程:
package main
import ("fmt"; "regexp"; "os"; "strings";)
func main () {
reg, error := regexp.Compile ("B");
if error != nil {
fmt.Printf ("编译失败:%s", error.String ());
os.Exit (1);
}
output := string (reg.ReplaceAll (strings.Bytes ("ABBA"),
strings.Bytes ("A")));
fmt.Println (output);
}
英文:
This is a routine to do what you want:
package main
import ("fmt"; "regexp"; "os"; "strings";);
func main () {
reg, error := regexp.Compile ("B");
if error != nil {
fmt.Printf ("Compile failed: %s", error.String ());
os.Exit (1);
}
output := string (reg.ReplaceAll (strings.Bytes ("ABBA"),
strings.Bytes ("A")));
fmt.Println (output);
}
答案2
得分: 1
这是一个小例子。你也可以在Regexp测试类中找到好的例子。
package main
import (
"fmt"
"regexp"
"strings"
)
func main() {
re, _ := regexp.Compile("e")
input := "hello"
replacement := "a"
actual := string(re.ReplaceAll(strings.Bytes(input), strings.Bytes(replacement)))
fmt.Printf("新模式 %s", actual)
}
英文:
Here is a small example. You can also find good examples in he Regexp test class
package main
import (
"fmt"
"regexp"
"strings"
)
func main() {
re, _ := regexp.Compile("e")
input := "hello"
replacement := "a"
actual := string(re.ReplaceAll(strings.Bytes(input), strings.Bytes(replacement)))
fmt.Printf("new pattern %s", actual)
}
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