英文:
Why does go require you to add & before a variable name?
问题
为什么你必须写 &t 而不是只写 t.req？
英文:
Here is a snippet that I am looking at:
var t txn
t.c = c
err := c.read(&t.req)
Why do you have to write &t and not just t.req?
答案1
得分: 6
你不总是需要使用 ampersand（&）。在你的例子中，这取决于 c.read 的签名，它要求一个指针（在类型之前加上 *，比如 *MyStruct）。& 返回一个值的地址，给你一个指向它的指针，所以 &t.req 满足 read 的签名。
英文:
You don't always have to use the ampersand. In your example it depends on the signature of c.read, which asks for a pointer (* before the type, such as *MyStruct). & returns the address of a value, giving you a pointer to it, so &t.req satisfies read's signature.
For further reading, see the FAQ on pointers and the spec on Address operators.
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