英文:
Go — how to handle common fields between struct types
问题
如果我有两种类型：
type A struct {
X int
Y int
}
type B struct {
X int
Y int
Z int
}
是否有办法在不需要两个方法的情况下实现以下功能，假设两者都访问具有相同名称的字段并返回它们的总和？
func (a *A) Sum() int {
return a.X + a.Y
}
func (b *B) Sum() int {
return b.X + b.Y
}
当然，如果X和Y是方法，我可以定义一个包含这两个方法的接口。是否有类似于字段的类比？
英文:
If I have two types:
type A struct {
X int
Y int
}
type B struct {
X int
Y int
Z int
}
Is there any way to achieve the following without needing two methods, given that both access identically-named fields and return the sum of them?
func (a *A) Sum() int {
return a.X + a.Y
}
func (b *B) Sum() int {
return b.X + b.Y
}
Of course, were X and Y methods, I could define an interface containing these two methods. Is there an analogue for fields?
答案1
得分: 13
嵌入A在B中。
type A struct {
X int
Y int
}
func (a *A) Sum() int {
return a.X + a.Y
}
type B struct {
*A
Z int
}
a := &A{1,2}
b := &B{&A{3,4},5}
fmt.Println(a.Sum(), b.Sum()) // 3 7
http://play.golang.org/p/fjT9c-m_Lj
但是，没有字段的接口。只有方法。
英文:
Embed A in B.
type A struct {
X int
Y int
}
func (a *A) Sum() int {
return a.X + a.Y
}
type B struct {
*A
Z int
}
a := &A{1,2}
b := &B{&A{3,4},5}
fmt.Println(a.Sum(), b.Sum()) // 3 7
http://play.golang.org/p/fjT9c-m_Lj
But no, there's no interface for fields. Only methods.
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