英文:
Size in bytes of the content of a slice
问题
我正在尝试向OpenGL发送一些数据。通过Sizeof,发送一个数组很容易:
array := [...]Whatever {lots of data}
array_ptr := gl.Pointer(&array[0])
array_size := gl.Sizeiptr(unsafe.Sizeof(array))
gl.BufferData(gl.ARRAY_BUFFER, array_size, array_ptr, gl.STATIC_DRAW)
我想使用切片而不是数组,因为我的3D模型的大小在编译时是未知的。
**如何获取切片内容的大小(以字节为单位)?**我想到了这个方法:
size := uintptr(len(slice)) * unsafe.Sizeof(slice[0])
但这不是很通用。实际上,我需要知道切片的底层类型才能使其工作,并且这假设数组的所有元素都具有相同的大小。
我也可以遍历整个切片并添加每个元素的大小。但这不是很快。
我准备始终保持len(s)==cap(s),这能帮助我吗?
编辑:使用运行时反射实现提议的解决方案
package main
import "fmt"
import "reflect"
func ElemSize(container interface{}) uintptr {
return reflect.TypeOf(container).Elem().Size()
}
func ElemSizeVerbose(container interface{}) uintptr {
t := reflect.TypeOf(container)
e := t.Elem()
s := e.Size()
fmt.Println(t, e, s)
return s
}
func main() {
a := [...]int8{2, 3, 5, 7, 11} // 数组
s := []int64{2, 3, 5, 7, 11} // 切片
z := []int32{} // 即使是空的
ElemSizeVerbose(a) // [5]int8 int8 1
ElemSizeVerbose(s) // []int64 int64 8
ElemSizeVerbose(z) // []int32 int32 4
}
英文:
I am trying to send some data to OpenGl. Sending an array is easy thanks to Sizeof:
array := [...]Whatever {lots of data}
array_ptr := gl.Pointer(&array[0])
array_size := gl.Sizeiptr(unsafe.Sizeof(array))
gl.BufferData(gl.ARRAY_BUFFER, array_size, array_ptr, gl.STATIC_DRAW)
I would like to use slices instead of arrays because the size of my 3D models is not known at compile time.
How do I retrieve the size, in bytes, of the content of a slice? I thought of this:
size := uintptr(len(slice)) * unsafe.Sizeof(slice[0])
but it is not very general. Indeed, I need to know the underlying type of the slice in order for this to work, and this supposes that all the elements of the array have the same size.
I could also loop over the whole slice and add all the sizes of every element. It's not very fast.
I am ready to always keep the len(s)==cap(s), can that help me?
Edit: implementation of the proposed solution using runtime reflection
package main
import "fmt"
import "reflect"
func ElemSize(container interface{}) uintptr {
return reflect.TypeOf(container).Elem().Size()
}
func ElemSizeVerbose(container interface{}) uintptr {
t := reflect.TypeOf(container)
e := t.Elem()
s := e.Size()
fmt.Println(t, e, s)
return s
}
func main() {
a := [...]int8{2, 3, 5, 7, 11} // Array
s := []int64{2, 3, 5, 7, 11} // Slice
z := []int32{} // Even empty things
ElemSizeVerbose(a) // [5]int8 int8 1
ElemSizeVerbose(s) // []int64 int64 8
ElemSizeVerbose(z) // []int32 int32 4
}
答案1
得分: 8
在切片或数组中,每个元素的大小始终相同。因此,只要len(s) > 0,您的示例就可以工作。换句话说,只要切片中至少有一个元素。否则,它将引发panic。
为了避免需要在切片中有一个元素,我建议使用以下方法:
uintptr(len(s)) * reflect.TypeOf(s).Elem().Size()
英文:
In a slice or array, every element is always the same size. Therefore, your example will work as long as len(s) > 0. In other words, as long as the slice has at least one element in it. Otherwise it will panic.
To avoid the need of having an element in the slice, I recommend using the following:
uintptr(len(s)) * reflect.TypeOf(s).Elem().Size()
答案2
得分: 3
你可以使用encoding/binary包的Size函数。
package main
import (
"encoding/binary"
"fmt"
)
func main() {
a := [...]int8{2, 3, 5, 7, 11} // 数组
s := []int64{2, 3, 5, 7, 11} // 切片
z := []int32{} // 即使是空的也可以
fmt.Println(binary.Size(a)) // 5
fmt.Println(binary.Size(s)) // 40
fmt.Println(binary.Size(z)) // 0
}
英文:
you can use (size) of the encoding/binary package.
package main
import (
"encoding/binary"
"fmt"
)
func main() {
a := [...]int8{2, 3, 5, 7, 11} // Array
s := []int64{2, 3, 5, 7, 11} // Slice
z := []int32{} // Even empty things
fmt.Println(binary.Size(a)) // 5
fmt.Println(binary.Size(s)) // 40
fmt.Println(binary.Size(z)) // 0
}
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