英文:
Go: edit in place of map values
问题
我在golang.org上使用Go Playground编写了一个简单的程序。
输出显然是：
second testfirst test
有没有办法直接在地图中编辑值？我知道我不能获取a.Things[key]的地址。那么，设置a.Things[key] = firstTest是唯一的方法吗？也许可以使用一个函数ChangeThing(key string, value string)吗？
英文:
I wrote a simple program using the Go Playground at golang.org.
The output is obviously:
second testfirst test
Is there a way to edit the map value in place? I know I can't take the andress of a.Things[key]. So, is setting a.Things[key] = firstTest the only way to do it? Maybe with a function ChangeThing(key string, value string)?
答案1
得分: 6
你可以通过将map的值指向另一个结构体来实现。
package mainimport "fmt"type A struct {Things map[string]*str}type str struct {s string}func (a A) ThingWithKey(key string) *str {return a.Things[key]}func main() {variable := A{}variable.Things = make(map[string]*str)variable.Things["first"] = &str{s:"first test"}firstTest := variable.ThingWithKey("first")firstTest.s = "second test"fmt.Println(firstTest.s)fmt.Println(variable.ThingWithKey("first").s)}
英文:
You could do it by making the values of your map pointers to another struct.
http://play.golang.org/p/UouwDGuVpi
package mainimport "fmt"type A struct {Things map[string]*str}type str struct {s string}func (a A) ThingWithKey(key string) *str {return a.Things[key]}func main() {variable := A{}variable.Things = make(map[string]*str)variable.Things["first"] = &str{s:"first test"}firstTest := variable.ThingWithKey("first")firstTest.s = "second test"fmt.Println(firstTest.s)fmt.Println(variable.ThingWithKey("first").s)}
答案2
得分: 3
你可以将指针用作地图值。
英文:
You can use a pointer as the map value http://play.golang.org/p/BCsmhevGMX
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