从整数转换为二进制表示形式

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英文:

Converting from an integer to its binary representation

问题

有没有人知道Go语言中是否有内置功能可以将任何一种数字类型转换为二进制形式。

例如,如果输入为123,则输出为字符串"1111011"

英文:

Has anyone got an idea if there is any inbuilt functionality in Go for converting from any one of the numeric types to its binary number form.

For example, if 123 was the input, the string "1111011" would be the output.

答案1

得分: 147

The strconv package has FormatInt function, which accepts an int64 and allows you to specify the base.

n := int64(123)

fmt.Println(strconv.FormatInt(n, 2)) // 1111011

DEMO: http://play.golang.org/p/leGVAELMhv

>http://golang.org/pkg/strconv/#FormatInt

>func FormatInt(i int64, base int) string

>FormatInt函数返回给定基数下i的字符串表示,其中2 <= base <= 36。结果使用小写字母'a'到'z'表示大于等于10的数字值。

英文:

The strconv package has FormatInt, which accepts an int64 and lets you specify the base.

n := int64(123)

fmt.Println(strconv.FormatInt(n, 2)) // 1111011

DEMO: http://play.golang.org/p/leGVAELMhv

>http://golang.org/pkg/strconv/#FormatInt

>func FormatInt(i int64, base int) string

>FormatInt returns the string representation of i in the given base, for 2 <= base <= 36. The result uses the lower-case letters 'a' to 'z' for digit values >= 10.

答案2

得分: 81

参见fmt包:

n := int64(123)
fmt.Printf("%b", n)  // 1111011
英文:

See also the fmt package:

n := int64(123)
fmt.Printf(&quot;%b&quot;, n)  // 1111011

答案3

得分: 15

package main

import . "fmt"

func main(){
    Printf("%d == %08b\n",0,0)
    Printf("%d == %08b\n",1,1)
    Printf("%d == %08b\n",2,2)
    Printf("%d == %08b\n",3,3)
    Printf("%d == %08b\n",4,4)
    Printf("%d == %08b\n",5,5)
}

结果为:

0 == 00000000
1 == 00000001
2 == 00000010
3 == 00000011
4 == 00000100
5 == 00000101
英文:
package main

import . &quot;fmt&quot;

func main(){
    Printf(&quot;%d == %08b\n&quot;,0,0)
    Printf(&quot;%d == %08b\n&quot;,1,1)
    Printf(&quot;%d == %08b\n&quot;,2,2)
    Printf(&quot;%d == %08b\n&quot;,3,3)
    Printf(&quot;%d == %08b\n&quot;,4,4)
    Printf(&quot;%d == %08b\n&quot;,5,5)
}

results in:

0 == 00000000
1 == 00000001
2 == 00000010
3 == 00000011
4 == 00000100
5 == 00000101

答案4

得分: 11

这段代码适用于大整数 *big.Int

x := big.NewInt(123)
s := fmt.Sprintf("%b", x)
// s == "1111011"

因为 *big.Int 实现了 fmt.Formatter 接口。

引用自 https://stackoverflow.com/a/23317788/871134

英文:

This code works on big integers *big.Int :

x := big.NewInt(123)
s := fmt.Sprintf(&quot;%b&quot;, x)
// s == &quot;1111011&quot;

because *big.Int implements the fmt.Formatter interface.

Taken from https://stackoverflow.com/a/23317788/871134

答案5

得分: 4

一个替代的方法是简单地执行以下操作:

s := fmt.Sprintf("%b", 123)
fmt.Println(s)                 // 1111011

为了获得更丰富的表示,您可以使用unsafe包(强烈不推荐):

a := int64(123)
byteSliceRev := *(*[8]byte)(unsafe.Pointer(&a))
byteSlice := make([]byte, 8)
for i := 0; i < 8; i++ {
    byteSlice[i] = byteSliceRev[7 - i]
}
fmt.Printf("%b\n", byteSlice)

这也适用于负整数。

英文:

An alternate way for the accepted answer would be to simply do

s := fmt.Sprintf(&quot;%b&quot;, 123)
fmt.Println(s)                 // 1111011

For a more rich representation you can use the unsafe package(strongly discouraged) as

a := int64(123)
byteSliceRev := *(*[8]byte)(unsafe.Pointer(&amp;a))
byteSlice := make([]byte, 8)
for i := 0; i &lt; 8; i++ {
	byteSlice[i] = byteSliceRev[7 - i]
}
fmt.Printf(&quot;%b\n&quot;, byteSlice)

This works for negative integers too.

答案6

得分: 3

建立在@Mark提供的答案基础上

尽管OP问如何打印一个整数,但我经常想查看超过64位的数据,而不让我的眼睛迷茫:

/* --- Credit to Dave C in the comments --- */
package main

import (
	"bytes"
	"fmt"
)

func main() {
	fmt.Printf("<%s>\n", fmtBits([]byte{0xDE, 0xAD, 0xBE, 0xEF, 0xF0, 0x0D, 0xDE, 0xAD, 0xBE, 0xEF, 0xF0, 0x0D}))
    
	// OUTPUT:
	// <11011110 10101101 10111110 11101111 11110000 00001101 11011110 10101101 10111110 11101111 11110000 00001101>
}

func fmtBits(data []byte) []byte {
	var buf bytes.Buffer
	for _, b := range data {
		fmt.Fprintf(&buf, "%08b ", b)
	}
	buf.Truncate(buf.Len() - 1) // To remove extra space
	return buf.Bytes()
}

在play.golang.org中查看此代码

英文:

Building on the answer provided by @Mark

Although the OP asked how to print an integer, I often want to look at more then 64 bits worth of data, without my eyes boggling:

/* --- Credit to Dave C in the comments --- */
package main

import (
	&quot;bytes&quot;
	&quot;fmt&quot;
)

func main() {
	fmt.Printf(&quot;&lt;%s&gt;\n&quot;, fmtBits([]byte{0xDE, 0xAD, 0xBE, 0xEF, 0xF0, 0x0D, 0xDE, 0xAD, 0xBE, 0xEF, 0xF0, 0x0D}))
    
	// OUTPUT:
	// &lt;11011110 10101101 10111110 11101111 11110000 00001101 11011110 10101101 10111110 11101111 11110000 00001101&gt;
}

func fmtBits(data []byte) []byte {
	var buf bytes.Buffer
	for _, b := range data {
		fmt.Fprintf(&amp;buf, &quot;%08b &quot;, b)
	}
	buf.Truncate(buf.Len() - 1) // To remove extra space
	return buf.Bytes()
}

<iframe src="https://play.golang.org/p/ifobZWv_du" frameborder="0" style="width: 100%; height: 100%"><a href="https://play.golang.org/p/ifobZWv_du">see this code in play.golang.org</a></iframe>

答案7

得分: 3

不安全指针必须用于正确表示二进制格式中的负数。

package main

import (
	"fmt"
	"strconv"
	"unsafe"
)

func bInt(n int64) string {
	return strconv.FormatUint(*(*uint64)(unsafe.Pointer(&n)), 2)
}

func main() {
	fmt.Println(bInt(-1))
}

https://play.golang.org/p/GxXjjWMyC4x

英文:

Unsafe pointers must be used to correctly represent negative numbers in binary format.

package main

import (
	&quot;fmt&quot;
	&quot;strconv&quot;
	&quot;unsafe&quot;
)

func bInt(n int64) string {
	return strconv.FormatUint(*(*uint64)(unsafe.Pointer(&amp;n)), 2)
}

func main() {
	fmt.Println(bInt(-1))
}

https://play.golang.org/p/GxXjjWMyC4x

答案8

得分: 1

Many above answers do not work if you use negative decimals.

Here is the simplest answer. Also works with negative decimals.

var a int64 = -1
fmt.Printf(&quot;%b\n&quot;, uint64(a)) // 11111.... (not -1)

(Go playground link)

You can also use fmt.Sprintf instead of fmt.Printf if you want a string variable.

This way, you can convert negative decimal into bitwise representation using two's complement (without - sign), not into mathematical binary representation (using - sign). (As I commented in Soslan's answer.)

(Soslan and Vaibhav's answers also work with negative numbers, using the unsafe package.)

英文:

Many above answers do not work if you use negative decimals.

Here is the simplest answer. Also works with negative decimals.

var a int64 = -1
fmt.Printf(&quot;%b\n&quot;, uint64(a)) // 11111.... (not -1)

(Go playground link)

You can also use fmt.Sprintf instead of fmt.Printf if you want a string variable.

This way, you can convert negative decimal into bitwise representation using two's complement (without - sign), not into mathematical binary representation (using - sign). (As I commented in Soslan's answer.)

(Soslan and Vaibhav's answers also work with negative numbers, using the unsafe package.)

答案9

得分: 0

package main

import (
	"bytes"
	"encoding/binary"
	"fmt"
	"time"
)

func main() {
	buf := new(bytes.Buffer)
	var x = time.Now().UnixNano()
	err := binary.Write(buf, binary.LittleEndian, x)
	if err != nil {
		fmt.Println("binary.Write failed:", err)
	}
	fmt.Printf("%v", buf.Bytes())
}
英文:
package main

import (
	&quot;bytes&quot;
	&quot;encoding/binary&quot;
	&quot;fmt&quot;
	&quot;time&quot;
)

func main() {
	buf := new(bytes.Buffer)
	var x = time.Now().UnixNano()
	err := binary.Write(buf, binary.LittleEndian, x)
	if err != nil {
		fmt.Println(&quot;binary.Write failed:&quot;, err)
	}
	fmt.Printf(&quot;%v&quot;, buf.Bytes())
}

huangapple
  • 本文由 发表于 2012年12月14日 08:17:54
  • 转载请务必保留本文链接:https://go.coder-hub.com/13870845.html
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