如何在Go中解析自纪元以来的毫秒时间戳字符串?

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英文:

How to parse a milliseconds-since-epoch timestamp string in Go?

问题

我有一个自纪元以来的毫秒字符串(它最初来自于java.lang.System.currentTimeMillis()调用)。在Go中,将此字符串转换为可读的时间戳字符串的正确方法是什么?

查看time包,我看到了Parse函数,但是布局似乎都是基于正常时区的时间。一旦转换为Time对象,我可以使用Format(Time.Stamp)来获得我想要的输出,但是我不清楚如何将字符串转换为Time对象。

英文:

I've got a string with milliseconds since the epoch (it came originally from a java.lang.System.currentTimeMillis() call). What's the right way to convert this string into a human readable timestamp string in Go?

Looking at the time package I see the Parse function, but the layouts all seem to be normal timezone-based times. Once into a Time object, I can use Format(Time.Stamp) to get the output I want, but I'm not clear on how to get the string into a Time object.

答案1

得分: 41

格式字符串不支持自纪元以来的毫秒数,因此您需要手动解析。例如:

func msToTime(ms string) (time.Time, error) {
    msInt, err := strconv.ParseInt(ms, 10, 64)
    if err != nil {
        return time.Time{}, err
    }

    return time.Unix(0, msInt*int64(time.Millisecond)), nil
}

请访问http://play.golang.org/p/M1dWGLT8XE以实时尝试示例。

英文:

The format string does not support milliseconds since the epoch, so you need to parse manually. For example:

func msToTime(ms string) (time.Time, error) {
    msInt, err := strconv.ParseInt(ms, 10, 64)
    if err != nil {
        return time.Time{}, err
    }

    return time.Unix(0, msInt*int64(time.Millisecond)), nil
}

Check out http://play.golang.org/p/M1dWGLT8XE to play with the example live.

答案2

得分: 5

2021更新:您可以使用UnixMilli函数来从整数解析时间。这将改进接受的答案:

func msToTime(ms string) (time.Time, error) {
    msInt, err := strconv.ParseInt(ms, 10, 64)
    if err != nil {
        return time.Time{}, err
    }

    return time.UnixMilli(msInt), nil
}
英文:

2021 update: you can use UnixMilli to parse from the integer. This would improve the accepted answer to:

 func msToTime(ms string) (time.Time, error) {
    msInt, err := strconv.ParseInt(ms, 10, 64)
    if err != nil {
        return time.Time{}, err
    }

    return time.UnixMilli(msInt), nil
}

答案3

得分: 3

接受的答案对于一些日期范围来说,要么太远的未来,要么太远的过去是不起作用的,因为只有64位可以描述一个有限的日期范围(从纪元开始的正负300年)。

这将适用于可以用毫秒描述的整个范围:

var Epoch = time.Unix(0, 0)

func ParseMillisecondUnixTimestamp(s string) (time.Time, error) {
	ts, err := strconv.Atoi(s)
	if err != nil {
		return time.Time{}, err
	}

	return Epoch.Add(time.Duration(ts) * time.Millisecond), nil
}
英文:

The accepted answer will not work for some date ranges either too far in the future or too far in the past because only a limited date range can be described using 64 bits (plus or minus 300 years from Epoch).

This will work for the entire range describable by milliseconds:

var Epoch = time.Unix(0, 0)

func ParseMillisecondUnixTimestamp(s string) (time.Time, error) {
	ts, err := strconv.Atoi(s)
	if err != nil {
		return time.Time{}, err
	}

	return Epoch.Add(time.Duration(ts) * time.Millisecond), nil
}

答案4

得分: -1

使用time.Unix(ms/1000, 0)可以解决问题。

首先使用已知的关系1秒=1000毫秒将毫秒时间戳转换为Unix时间戳,然后将结果作为time.Unix函数的第一个参数使用。

英文:

Using time.Unix(ms/1000, 0) would do the trick.

First convert the ms-timestamp to unix-timestamp using the well known relation 1 s = 1000 ms and then use the result as first argument to the time.Unix function

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  • 本文由 发表于 2012年11月9日 01:41:08
  • 转载请务必保留本文链接:https://go.coder-hub.com/13294649.html
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