英文:
How do I dump the struct into the byte array without reflection?
问题
我已经找到了encoding/binary包来处理这个问题,但它依赖于reflect包,所以它不能处理未大写(即未导出)的结构字段。然而,尽管我花了一周的时间找出了这个问题,但我仍然有一个问题:如果结构字段不应该被导出,那么如何将它们轻松地转换为二进制数据呢?
**编辑:**这里是一个示例。如果将Data
结构的字段名称大写,那么它可以正常工作。但是Data
结构被设计为一个抽象类型,所以我不想导出这些字段。
package main
import (
"fmt"
"encoding/binary"
"bytes"
)
type Data struct {
id int32
name [16]byte
}
func main() {
d := Data{Id: 1}
copy(d.Name[:], []byte("tree"))
buffer := new(bytes.Buffer)
binary.Write(buffer, binary.LittleEndian, d)
// d was written properly
fmt.Println(buffer.Bytes())
// try to read...
buffer = bytes.NewBuffer(buffer.Bytes())
var e = new(Data)
err := binary.Read(buffer, binary.LittleEndian, e)
fmt.Println(e, err)
}
英文:
I already found encoding/binary package to deal with it, but it depended on reflect package so it didn't work with uncapitalized(that is, unexported) struct fields. However I spent a week to find that problem out, I still have a question: if struct fields should not be exported, how do I dump them easily into binary data?
EDIT: Here's the example. If you capitalize the name of fields of Data
struct, that works properly. But Data
struct was intended to be an abstract type, so I don't want to export these fields.
<!-- language: lang-go -->
package main
import (
"fmt"
"encoding/binary"
"bytes"
)
type Data struct {
id int32
name [16]byte
}
func main() {
d := Data{Id: 1}
copy(d.Name[:], []byte("tree"))
buffer := new(bytes.Buffer)
binary.Write(buffer, binary.LittleEndian, d)
// d was written properly
fmt.Println(buffer.Bytes())
// try to read...
buffer = bytes.NewBuffer(buffer.Bytes())
var e = new(Data)
err := binary.Read(buffer, binary.LittleEndian, e)
fmt.Println(e, err)
}
答案1
得分: 35
你最好的选择可能是使用gob包,并让你的结构体实现GobDecoder和GobEncoder接口,以便对私有字段进行序列化和反序列化。
这样做是安全的、与平台无关的和高效的。而且你只需要在具有未导出字段的结构体上添加这些GobEncode和GobDecode函数,这意味着你不会在代码的其他部分添加冗余代码。
func (d *Data) GobEncode() ([]byte, error) {
w := new(bytes.Buffer)
encoder := gob.NewEncoder(w)
err := encoder.Encode(d.id)
if err != nil {
return nil, err
}
err = encoder.Encode(d.name)
if err != nil {
return nil, err
}
return w.Bytes(), nil
}
func (d *Data) GobDecode(buf []byte) error {
r := bytes.NewBuffer(buf)
decoder := gob.NewDecoder(r)
err := decoder.Decode(&d.id)
if err != nil {
return err
}
return decoder.Decode(&d.name)
}
func main() {
d := Data{id: 7}
copy(d.name[:], []byte("tree"))
buffer := new(bytes.Buffer)
// writing
enc := gob.NewEncoder(buffer)
err := enc.Encode(d)
if err != nil {
log.Fatal("encode error:", err)
}
// reading
buffer = bytes.NewBuffer(buffer.Bytes())
e := new(Data)
dec := gob.NewDecoder(buffer)
err = dec.Decode(e)
fmt.Println(e, err)
}
英文:
Your best option would probably be to use the gob package and let your struct implement the GobDecoder and GobEncoder interfaces in order to serialize and deserialize private fields.
This would be safe, platform independent, and efficient. And you have to add those GobEncode and GobDecode functions only on structs with unexported fields, which means you don't clutter the rest of your code.
func (d *Data) GobEncode() ([]byte, error) {
w := new(bytes.Buffer)
encoder := gob.NewEncoder(w)
err := encoder.Encode(d.id)
if err!=nil {
return nil, err
}
err = encoder.Encode(d.name)
if err!=nil {
return nil, err
}
return w.Bytes(), nil
}
func (d *Data) GobDecode(buf []byte) error {
r := bytes.NewBuffer(buf)
decoder := gob.NewDecoder(r)
err := decoder.Decode(&d.id)
if err!=nil {
return err
}
return decoder.Decode(&d.name)
}
func main() {
d := Data{id: 7}
copy(d.name[:], []byte("tree"))
buffer := new(bytes.Buffer)
// writing
enc := gob.NewEncoder(buffer)
err := enc.Encode(d)
if err != nil {
log.Fatal("encode error:", err)
}
// reading
buffer = bytes.NewBuffer(buffer.Bytes())
e := new(Data)
dec := gob.NewDecoder(buffer)
err = dec.Decode(e)
fmt.Println(e, err)
}
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