redigo,SMEMBERS,如何获取字符串

huangapple go评论103阅读模式
英文:

redigo, SMEMBERS, how to get strings

问题

如何将类型为[]interface {}{[]byte{} []byte{}}的数据转换为一组字符串?在这种情况下,我想要得到两个字符串HelloWorld

英文:

I am redigo to connect from Go to a redis database. How can I convert a type of []interface {}{[]byte{} []byte{}} to a set of strings? In this case I'd like to get the two strings Hello and World.

package main

import (
	"fmt"
	"github.com/garyburd/redigo/redis"
)

func main() {
	c, err := redis.Dial("tcp", ":6379")
	defer c.Close()
	if err != nil {
		fmt.Println(err)
	}
	c.Send("SADD", "myset", "Hello")
	c.Send("SADD", "myset", "World")
	c.Flush()
	c.Receive()
	c.Receive()

	err = c.Send("SMEMBERS", "myset")
	if err != nil {
		fmt.Println(err)
	}
	c.Flush()
	// both give the same return value!?!?
	// reply, err := c.Receive()
	reply, err := redis.MultiBulk(c.Receive())
	if err != nil {
		fmt.Println(err)
	}
	fmt.Printf("%#v\n", reply)
	// $ go run main.go
	// []interface {}{[]byte{0x57, 0x6f, 0x72, 0x6c, 0x64}, []byte{0x48, 0x65, 0x6c, 0x6c, 0x6f}}
    // How do I get 'Hello' and 'World' from this data?
}

答案1

得分: 8

模块源代码中查找

// String是一个将Redis回复转换为字符串的辅助函数。
//
//  回复类型      结果
//  整数           格式为十进制字符串
//  块             作为字符串返回回复
//  字符串          原样返回
//  空             返回错误ErrNil
//  其他           返回错误
func String(v interface{}, err error) (string, error) {

redis.String将在(v interface{}, err error)中转换为(string, error)

reply, err := redis.MultiBulk(c.Receive())

替换为

s, err := redis.String(redis.MultiBulk(c.Receive()))
英文:

Look in module source code

// String is a helper that converts a Redis reply to a string. 
//
//  Reply type      Result
//  integer         format as decimal string
//  bulk            return reply as string
//  string          return as is
//  nil             return error ErrNil
//  other           return error
func String(v interface{}, err error) (string, error) {

redis.String will convert (v interface{}, err error) in (string, error)

reply, err := redis.MultiBulk(c.Receive())

replace with

s, err := redis.String(redis.MultiBulk(c.Receive()))

答案2

得分: 4

查看模块的源代码,你可以看到从Receive返回的类型签名将是:

func (c *conn) Receive() (reply interface{}, err error)

在你的情况下,你正在使用MultiBulk:

func MultiBulk(v interface{}, err error) ([]interface{}, error)

这将在一个切片中返回多个interface{}类型的回复:[]interface{}

在未指定类型的interface{}之前,你必须像这样断言其类型

x.(T)

其中T是一个类型(例如,intstring等)

在你的情况下,你有一个接口切片(类型为[]interface{}),所以如果你想要一个string,你需要首先断言每个元素的类型为[]byte,然后将它们转换为string,例如:

for _, x := range reply {
	var v, ok = x.([]byte)
	if ok {
		fmt.Println(string(v))
	}
}

这里有一个示例:http://play.golang.org/p/ZifbbZxEeJ

你还可以使用类型开关来检查返回的数据类型:

http://golang.org/ref/spec#Type_switches

for _, y := range reply {
    switch i := y.(type) {
    case nil:
    	printString("x is nil")
    case int:
    	printInt(i)  // i是一个int
    等等...
    }
}

或者,正如有人提到的,使用内置的redis.String等方法来检查和转换它们。

我认为关键是,每个元素都需要转换,你不能只是一次性转换它们(除非你编写一个方法来这样做!)。

英文:

Looking at the source code for the module, you can see the type signature returned from Receive will be:


func (c *conn) Receive() (reply interface{}, err error)

and in your case, you're using MultiBulk:


func MultiBulk(v interface{}, err error) ([]interface{}, error)

This gives a reply of multiple interface{} 's in a slice: []interface{}

Before an untyped interface{} you have to assert its type like so:

x.(T)

Where T is a type (eg, int, string etc.)

In your case, you have a slice of interfaces (type: []interface{}) so, if you want a string, you need to first assert that each one has type []bytes, and then cast them to a string eg:

for _, x := range reply {
	var v, ok = x.([]byte)
	if ok {
		fmt.Println(string(v))
	}
}

Here's an example: http://play.golang.org/p/ZifbbZxEeJ

You can also use a type switch to check what kind of data you got back:

http://golang.org/ref/spec#Type_switches

for _, y := range reply {
    switch i := y.(type) {
    case nil:
    	printString("x is nil")
    case int:
    	printInt(i)  // i is an int
    etc...
    }
}

Or, as someone mentioned, use the built in redis.String etc. methods which will check and convert them for you.

I think the key is, each one needs to be converted, you can't just do them as a chunk (unless you write a method to do so!).

答案3

得分: 1

由于redis.MultiBulk()现在已经被弃用,使用redis.Values()并将结果转换为String可能是一个好的方法:

import "github.com/gomodule/redigo/redis"

type RedisClient struct {
    Conn redis.Conn
}

func (r *RedisClient) SMEMBERS(key string) interface{} {
    tmp, err := redis.Values(r.Conn.Do("smembers", key))
    if err != nil {
        fmt.Println(err)
        return nil
    }
    res := make([]string, 0)
    for _, v := range tmp {
        res = append(res, string(v.([]byte)))
    }
    return res
}
英文:

Since redis.MultiBulk() now is deprecated, it might be a good way to use redis.Values() and convert the result into String:

import "github.com/gomodule/redigo/redis"

type RedisClient struct {
	Conn      redis.Conn
}

func (r *RedisClient) SMEMBERS(key string) interface{} {
	tmp, err := redis.Values(r.Conn.Do("smembers", key))
	if err != nil {
		fmt.Println(err)
		return nil
	}
	res := make([]string, 0)
	for _, v := range tmp {
		res = append(res, string(v.([]byte)))
	}
	return res
}

huangapple
  • 本文由 发表于 2012年9月28日 04:49:45
  • 转载请务必保留本文链接:https://go.coder-hub.com/12629801.html
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