英文:
Can a Go struct inherit a set of values?
问题
一个Go结构体能够从另一个结构体类型继承一组值吗？
类似于这样的情况。
type Foo struct {Val1, Val2, Val3 int}var f *Foo = &Foo{123, 234, 354}type Bar struct {// 以某种方式在这里添加f，以便在“Bar”继承中使用OtherVal string}
这样我就可以这样做。
b := Bar{"test"}fmt.Println(b.Val2) // 234
如果不行，有什么技术可以实现类似的效果？
英文:
Can a Go struct inherit a set of values from a type of another struct?
Something like this.
type Foo struct {Val1, Val2, Val3 int}var f *Foo = &Foo{123, 234, 354}type Bar struct {// somehow add the f here so that it will be used in "Bar" inheritanceOtherVal string}
Which would let me do this.
b := Bar{"test"}fmt.Println(b.Val2) // 234
If not, what technique could be used to achieve something similar?
答案1
得分: 9
这是如何在Bar结构体中嵌入Foo结构体的方法：
type Foo struct {Val1, Val2, Val3 int}type Bar struct {FooOtherVal string}func main() {f := &Foo{123, 234, 354}b := &Bar{*f, "test"}fmt.Println(b.Val2) // 打印234f.Val2 = 567fmt.Println(b.Val2) // 仍然打印234}
现在假设你不想复制值，并且希望b在f改变时也改变。那么你不想使用嵌入，而是使用指针进行组合：
type Foo struct {Val1, Val2, Val3 int}type Bar struct {*FooOtherVal string}func main() {f := &Foo{123, 234, 354}b := &Bar{f, "test"}fmt.Println(b.Val2) // 234f.Val2 = 567fmt.Println(b.Val2) // 567}
两种不同类型的组合，具有不同的能力。
英文:
Here's how you may embed the Foo struct in the Bar one :
type Foo struct {Val1, Val2, Val3 int}type Bar struct {FooOtherVal string}func main() {f := &Foo{123, 234, 354}b := &Bar{*f, "test"}fmt.Println(b.Val2) // prints 234f.Val2 = 567fmt.Println(b.Val2) // still 234}
Now suppose you don't want the values to be copied and that you want b to change if f changes. Then you don't want embedding but composition with a pointer :
type Foo struct {Val1, Val2, Val3 int}type Bar struct {*FooOtherVal string}func main() {f := &Foo{123, 234, 354}b := &Bar{f, "test"}fmt.Println(b.Val2) // 234f.Val2 = 567fmt.Println(b.Val2) // 567}
Two different kind of composition, with different abilities.
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