Appengine > Go > 映射数据存储结果

huangapple go评论75阅读模式
英文:

Appengine > Go > Mapping datastore results

问题

我正在尝试映射通过query.GetAll()检索到的结果。

我需要映射结果,因为模板将需要与每个实体关联的数据存储'Key'。

目前我正在做以下操作:

// 查询
q := datastore.NewQuery("Article").Limit(10)
// 定义用于检索实体的数组
var a[] Article;
// 检索实体
key, _ := q.GetAll(c, &a)
// 创建一个空映射
article := map[string] Article{}
// 构建映射
for k := range a {
    article[key[k].Encode()] = a[k];
}
template.Execute(w, map[string]interface{} { "Articles" : article})

是否有一种更高效的方法直接使用query.GetAll()构建映射,因为创建一个数组、一个映射并循环遍历数组来构建映射似乎不明智?

或者有一种更高效的方法来获取与每个实体关联的数据存储Key(编码)?

英文:

I'm trying to map the results retreived by query.GetAll()

I need to map the results since the Template will need the datastore 'Key' associated with each entity.

At the moment I'm doing the following:

// Query
q := datastore.NewQuery("Article").Limit(10)
// Define array where the entities will be retreived
var a[] Article;
// Retreive entities
key, _ := q.GetAll(c, &a)
// Create an empty map
article := map[string] Article{}
// Build the map
for k := range a {
	article[key[k].Encode()] = a[k];
}
template.Execute(w, map[string]interface{} { "Articles" : article})

Is there a more efficient way to build the map directly using query.GetAll(), since creating an array, a map and loop over the array to build the map doesn't seem wise?

Or a more efficient way to get the datastore Key (Encoded) associated with each entity?

答案1

得分: 1

也许最好的方法是将切片压缩成一个单一的切片。按照这个思路,

package main

import (
    "os"
    "text/template"
)

type pair struct {
    Key     string
    Article string
}

var tmpt = `Here's the list:{{range $p := .}}
    {{$p.Key}}: {{$p.Article}}{{end}}
`

func main() {
    list := template.Must(template.New("list").Parse(tmpt))
    // 查询
    key := []string{"banana", "donkey", "curious"}
    a := []string{"长水果", "谁需要一个?", "人性"}
    // 压缩
    pairs := make([]pair, len(key))
    for i, k := range key {
        pairs[i].Key = k
        pairs[i].Article = a[i]
    }
    // 在压缩的列表上执行
    if err := list.Execute(os.Stdout, pairs); err != nil {
        os.Stdout.WriteString(err.Error())
    }
}

输出:

Here's the list:
        banana: 长水果
        donkey: 谁需要一个?
        curious: 人性
英文:

Maybe best is to zip the slices into a single slice. Along these lines,

package main

import (
    "os"
    "text/template"
)

type pair struct {
    Key     string
    Article string
}

var tmpt = `Here's the list:{{range $p := .}}
    {{$p.Key}}: {{$p.Article}}{{end}}
`

func main() {
    list := template.Must(template.New("list").Parse(tmpt))
    // query
    key := []string{"banana", "donkey", "curious"}
    a := []string{"long fruit", "who needs one?", "human nature"}
    // zip
    pairs := make([]pair, len(key))
    for i, k := range key {
        pairs[i].Key = k
        pairs[i].Article = a[i]
    }
    // execute on zipped list
    if err := list.Execute(os.Stdout, pairs); err != nil {
        os.Stdout.WriteString(err.Error())
    }
}

Output:
<pre>
Here's the list:
banana: long fruit
donkey: who needs one?
curious: human nature
</pre>

答案2

得分: 0

我认为你不需要使用map。如果我理解正确,在GetAll之后,你有两个并行的切片,key和a。(我不了解GAE,但是_让我感到疑惑。这是你应该检查的东西吗?)模板可以处理并行数组。在文档中可以看到range操作可以返回两个结果,一个是值,一个是索引。你应该可以遍历一个切片,并使用索引从另一个切片中获取相应的值。这将是一个更复杂的模板,但应该可以避免使用map。

编辑:抱歉,我以为我知道如何做到这一点,但是当我尝试编写一个示例代码时失败了。我会把它留在这里,以防其他人知道如何做到这一点,否则请投反对票...

英文:

I don't think you need the map. If I understand, after GetAll, you have two parallel slices, key and a. (I don't know GAE, but the _ raises my eyebrow. Is it something you should check?) Templates can handle parallel arrays. See in the doc how the range action can return two results, a value and and index. You should be able to range over one slice and use the index to get corresponding values from the other. It will be a more complex template, but should let you avoid the map.

Edit: Sorry, I thought I knew how to do this, but failed when I tried to code an example. I'll leave it here in case someone else knows how to do this, otherwise, downvote...

答案3

得分: 0

也许你可以将Key嵌入到Article中。你仍然需要循环遍历文章和键,但至少不需要创建一个单独的映射。

type Article struct {
    // 将键添加到结构体中,但防止它保存到数据存储中。
    Key datastore.Key `datastore:"-"`
}

// 查询
q := datastore.NewQuery("Article").Limit(10)
// 定义用于检索实体的数组
var a []Article
// 检索实体
key, _ := q.GetAll(c, &a)

// 循环遍历文章并在遍历过程中添加键。
for i := range a {
    a[i].Key = key[i]
}
template.Execute(w, map[string]interface{}{"Articles": a})

然后在你的模板中调用article.Key.Encode

英文:

Maybe you could embedding the Key in the Article. You would still have to loop over the articles and keys, but at least you wouldn't have to create a separate map.

type Article struct {
    // Add a key to the struct, but prevent it from being saved to the datastore.
    Key datastore.Key `datastore:&quot;-&quot;`
}

// Query
q := datastore.NewQuery(&quot;Article&quot;).Limit(10)
// Define array where the entities will be retreived
var a[] Article
// Retreive entities
key, _ := q.GetAll(c, &amp;a)

// Loop through the articles adding the key as you go.
for i := range a {
    a[i].Key = key[i]
}
template.Execute(w, map[string]interface{} { &quot;Articles&quot; : a})

Then in your template you would call article.Key.Encode

huangapple
  • 本文由 发表于 2012年4月30日 08:04:49
  • 转载请务必保留本文链接:https://go.coder-hub.com/10377121.html
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