英文:
Appengine > Go > Mapping datastore results
问题
我正在尝试映射通过query.GetAll()检索到的结果。
我需要映射结果,因为模板将需要与每个实体关联的数据存储'Key'。
目前我正在做以下操作:
// 查询
q := datastore.NewQuery("Article").Limit(10)
// 定义用于检索实体的数组
var a[] Article;
// 检索实体
key, _ := q.GetAll(c, &a)
// 创建一个空映射
article := map[string] Article{}
// 构建映射
for k := range a {
article[key[k].Encode()] = a[k];
}
template.Execute(w, map[string]interface{} { "Articles" : article})
是否有一种更高效的方法直接使用query.GetAll()构建映射,因为创建一个数组、一个映射并循环遍历数组来构建映射似乎不明智?
或者有一种更高效的方法来获取与每个实体关联的数据存储Key(编码)?
英文:
I'm trying to map the results retreived by query.GetAll()
I need to map the results since the Template will need the datastore 'Key' associated with each entity.
At the moment I'm doing the following:
// Query
q := datastore.NewQuery("Article").Limit(10)
// Define array where the entities will be retreived
var a[] Article;
// Retreive entities
key, _ := q.GetAll(c, &a)
// Create an empty map
article := map[string] Article{}
// Build the map
for k := range a {
article[key[k].Encode()] = a[k];
}
template.Execute(w, map[string]interface{} { "Articles" : article})
Is there a more efficient way to build the map directly using query.GetAll(), since creating an array, a map and loop over the array to build the map doesn't seem wise?
Or a more efficient way to get the datastore Key (Encoded) associated with each entity?
答案1
得分: 1
也许最好的方法是将切片压缩成一个单一的切片。按照这个思路,
package main
import (
"os"
"text/template"
)
type pair struct {
Key string
Article string
}
var tmpt = `Here's the list:{{range $p := .}}
{{$p.Key}}: {{$p.Article}}{{end}}
`
func main() {
list := template.Must(template.New("list").Parse(tmpt))
// 查询
key := []string{"banana", "donkey", "curious"}
a := []string{"长水果", "谁需要一个?", "人性"}
// 压缩
pairs := make([]pair, len(key))
for i, k := range key {
pairs[i].Key = k
pairs[i].Article = a[i]
}
// 在压缩的列表上执行
if err := list.Execute(os.Stdout, pairs); err != nil {
os.Stdout.WriteString(err.Error())
}
}
输出:
Here's the list: banana: 长水果 donkey: 谁需要一个? curious: 人性
英文:
Maybe best is to zip the slices into a single slice. Along these lines,
package main
import (
"os"
"text/template"
)
type pair struct {
Key string
Article string
}
var tmpt = `Here's the list:{{range $p := .}}
{{$p.Key}}: {{$p.Article}}{{end}}
`
func main() {
list := template.Must(template.New("list").Parse(tmpt))
// query
key := []string{"banana", "donkey", "curious"}
a := []string{"long fruit", "who needs one?", "human nature"}
// zip
pairs := make([]pair, len(key))
for i, k := range key {
pairs[i].Key = k
pairs[i].Article = a[i]
}
// execute on zipped list
if err := list.Execute(os.Stdout, pairs); err != nil {
os.Stdout.WriteString(err.Error())
}
}
Output:
<pre>
Here's the list:
banana: long fruit
donkey: who needs one?
curious: human nature
</pre>
答案2
得分: 0
我认为你不需要使用map。如果我理解正确,在GetAll之后,你有两个并行的切片,key和a。(我不了解GAE,但是_让我感到疑惑。这是你应该检查的东西吗?)模板可以处理并行数组。在文档中可以看到range操作可以返回两个结果,一个是值,一个是索引。你应该可以遍历一个切片,并使用索引从另一个切片中获取相应的值。这将是一个更复杂的模板,但应该可以避免使用map。
编辑:抱歉,我以为我知道如何做到这一点,但是当我尝试编写一个示例代码时失败了。我会把它留在这里,以防其他人知道如何做到这一点,否则请投反对票...
英文:
I don't think you need the map. If I understand, after GetAll, you have two parallel slices, key and a. (I don't know GAE, but the _ raises my eyebrow. Is it something you should check?) Templates can handle parallel arrays. See in the doc how the range action can return two results, a value and and index. You should be able to range over one slice and use the index to get corresponding values from the other. It will be a more complex template, but should let you avoid the map.
Edit: Sorry, I thought I knew how to do this, but failed when I tried to code an example. I'll leave it here in case someone else knows how to do this, otherwise, downvote...
答案3
得分: 0
也许你可以将Key
嵌入到Article
中。你仍然需要循环遍历文章和键,但至少不需要创建一个单独的映射。
type Article struct {
// 将键添加到结构体中,但防止它保存到数据存储中。
Key datastore.Key `datastore:"-"`
}
// 查询
q := datastore.NewQuery("Article").Limit(10)
// 定义用于检索实体的数组
var a []Article
// 检索实体
key, _ := q.GetAll(c, &a)
// 循环遍历文章并在遍历过程中添加键。
for i := range a {
a[i].Key = key[i]
}
template.Execute(w, map[string]interface{}{"Articles": a})
然后在你的模板中调用article.Key.Encode
。
英文:
Maybe you could embedding the Key
in the Article
. You would still have to loop over the articles and keys, but at least you wouldn't have to create a separate map.
type Article struct {
// Add a key to the struct, but prevent it from being saved to the datastore.
Key datastore.Key `datastore:"-"`
}
// Query
q := datastore.NewQuery("Article").Limit(10)
// Define array where the entities will be retreived
var a[] Article
// Retreive entities
key, _ := q.GetAll(c, &a)
// Loop through the articles adding the key as you go.
for i := range a {
a[i].Key = key[i]
}
template.Execute(w, map[string]interface{} { "Articles" : a})
Then in your template you would call article.Key.Encode
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