英文: Why does specifying a lifetime let me return a reference? 问题 I'm struggling to understand lifeti...
Can't Deserialize in generic trait function due to lifetime issue, but it works when out of generic function
英文: Can't Deserialize in generic trait function due to lifetime issue, but it works when out of ...
寿命扣除和在通用函数中借用(用于通用测试)
英文: Lifetime deduction and borrowing in generic functions (required for generic-tests) 问题 以下是翻译好的代码部...
如何建立与较高排名的特质限制相关的关系
英文: How to establish relation with respect to higher ranked trait bounds 问题 fn static_dispatcher<...
参数类型可能不会存活足够长时间(再次?)(在闭包中)
英文: the parameter type may not live long enough (again?) (in closure) 问题 在尝试编译以下代码时: ```rust fn make...
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